The domain of y = v2 – x is A. (-0,2] B. (-0,00) C. (-∞,2) D. [2,0) E. 0

Q: (x + 5)/(x – 3) is NOT defined for x =   a. 3   b. 0   c. -3   d. -5

A:

Q: 6x + 5 > -2(x – 3) – 25

A: 6x + 5 > -2(x-3) - 25 6x + 5 > -2x + 6 - 25 Add (2x) on both side 8x + 5 > -19

Q: Let_Z1 = 3 + i and Z2 = 5 + 2 i . Find 2 Z1 /( Z1 - Z2) - (14/5)-2 i O (14/5) + 2i O - (14 / 5) + (…

A: Topic = Complex number

Q: (22) Let A = (-∞, -2] and B = (102, ∞).

A: Given A=(-∞, -2] , B=(102, ∞). Now, the union of two sets consists all those elements that belong to…

Q: Find L{t?e-4t - e-2tsin (v2t)}

A:

Q: (x - 3 bxy + 2 b?y?) (xdx + ydy) = xdy-ydx %3D

A:

Q: 2x+2 y = 5

A: Given : 2x+2y = 5x+y = 3

Q: Let A=(¹). 3¹). Find 3A³2A² + 5A - 12.

A: Given: A=1-123 We are required to find: 3A3-2A2+5A-I2

Q: 6. Determine the domain of the following: a. y = -3/14 + 3x b. y = V4 + 3x –- x² x+1 С. у %3 х(х-2)…

A: Domain of given function at which y(x) is defined.

Q: Determine fy (y3 +3y) dy 3 4. 1Y +3y+ C 4 11 11 3 11 y +y +C 11 11 .4 3 3 3. IL D Boş bırak 2.

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Q: 2 -1 2 2.

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Q: (x*2)+(y*1.5)+(z*0.5)=20 find the values of X, Y, & Z

A: Please see the below answer.

Q: d. x+3y = 0 y-4+ 4(x - 2) f. -6x + 4y -7 Find intercent and v-intercent.

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Q: K (x2.V1) (1-Y1)

A: Determine the length of LK

Q: .2 y = 4 - x² and x +y = 2.

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Q: If (x and jy)² = 3 + j8, find x and y.

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Q: -1 -x d. Let A = 2 2 1 2 i. |A| =

A: Given that: A=-x-1-xx2x212

Q: (1 + 1)e dr 5.

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Q: 2 D²y+y=secx²

A:

Q: = (2xy + z² )i + (x² +z)j + (y + 2xz)k, determine a possible value for .

A:

Q: Determine the right end behavior of y = - 13x + +3x². + 1x4 As x → ∞0, Oy → +∞ y → -∞ Oy → -13 Oy -…

A: y=-13x+13x2+14x4if degree is even and leading coefficient is positive than as x→-∞, f(x)→∞ as x→∞,…

Q: Exc. Eind. Lim (x-1) y3

A: Solution:

Q: If (x + 1, y – 2) = (3,1), find the values of x and y.

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Q: Q.2 a. Find the Domain for y- /4 -x +

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Q: Find xy² Una -dA, R= [0,4] × [-2, 2] x² + 1

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Q: 2a - 5y dA, R =(-5,4] x [0, 3] R.

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Q: y = x² + x y = x + 5 2

A: y=x2+x y=x+5   a2-b2=(a-b)(a+b)

Q: Find the J(2x + 1)³ dx

A: