The divided difference table above is for the data: are: (3) x a -0.2 a) Do not apply any rounding. = 0.0 0.1 f(x) 0.70280 0.13534 -0.14943 For the second degree polynomial, P₂(x), with starting node x3 = 0.5, obtained with the divided difference method (by reading the divided difference table from the downside up), and that passes through the points (0.0,0.13534), (0.1,-0.14943) and (0.5,-1.1518), the coefficients 0.5 0.7 -1.1518 -1.4845 a(²) =
The divided difference table above is for the data: are: (3) x a -0.2 a) Do not apply any rounding. = 0.0 0.1 f(x) 0.70280 0.13534 -0.14943 For the second degree polynomial, P₂(x), with starting node x3 = 0.5, obtained with the divided difference method (by reading the divided difference table from the downside up), and that passes through the points (0.0,0.13534), (0.1,-0.14943) and (0.5,-1.1518), the coefficients 0.5 0.7 -1.1518 -1.4845 a(²) =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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are:
a(3) =
The divided difference table above is for the data:
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The error in pol X
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f(x) 0.70280
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a) Do not apply any rounding.
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For the second degree polynomial, P₂(x), with starting node x3 = 0.5,
obtained with the divided difference method (by reading the divided
difference table from the downside up), and that passes through the
points (0.0,0.13534), (0.1,-0.14943) and (0.5,-1.1518), the coefficients
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7
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Time Remaining: 00:05:49
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