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← The distribution of scores on a test for a particular class is skewed to the right. The professor wants to predict the maximum score and understand the of the sample maximum. She simulates the distribution of the maximum of the test for 37 different tests (with n=5). The histogram to the right shows a simulated sampling distribution of the sample maximum from these tests. Complete parts a) and b) below. distribution a) Would a Normal model be a useful model for this sampling distribution? Explain. A. No. The sapling distribution of the maximum is skewed to the right, so a Normal model would not be useful for this sampling distribution. OB. No. The sampling distribution of the maximum is symmetric and unimodal, so a Normal model would not be useful for this sampling distribution OC. Yes. The sampling distribution of the maximum is symmetric and unimodal, so a Normal model would be useful for this sampling distribution OD. Yes. The sampling distribution of the maximum is skewed to the right, so a Normal model would be useful for this sampling distribution. b) The mean of this distribution is 46.2 and the SD is 3.5. Would you expect about 68% of the samples to have their maximums within 3.5 of 46.27 Why or why not? OA Yes. The 68-95-99.7 Rule is based on the Normal distribution OB. No. The values show too much variation to apply the 68-95-99.7 Rule. ⒸC. Yes. The values show too little variation to apply the 68-95-99.7 Rule. OD. No. The 68-95-99.7 Rule is based on the Normal distribution Frequency 154 45 50 Man Sore ddo

← The distribution of scores on a test for a particular class is skewed to the right. The professor wants to predict the maximum score and understand the of the sample maximum. She simulates the distribution of the maximum of the test for 37 different tests (with n=5). The histogram to the right shows a simulated sampling distribution of the sample maximum from these tests. Complete parts a) and b) below. distribution a) Would a Normal model be a useful model for this sampling distribution? Explain. A. No. The sapling distribution of the maximum is skewed to the right, so a Normal model would not be useful for this sampling distribution. OB. No. The sampling distribution of the maximum is symmetric and unimodal, so a Normal model would not be useful for this sampling distribution OC. Yes. The sampling distribution of the maximum is symmetric and unimodal, so a Normal model would be useful for this sampling distribution OD. Yes. The sampling distribution of the maximum is skewed to the right, so a Normal model would be useful for this sampling distribution. b) The mean of this distribution is 46.2 and the SD is 3.5. Would you expect about 68% of the samples to have their maximums within 3.5 of 46.27 Why or why not? OA Yes. The 68-95-99.7 Rule is based on the Normal distribution OB. No. The values show too much variation to apply the 68-95-99.7 Rule. ⒸC. Yes. The values show too little variation to apply the 68-95-99.7 Rule. OD. No. The 68-95-99.7 Rule is based on the Normal distribution Frequency 154 45 50 Man Sore ddo

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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K The distribution of scores on a test for a particular class is skewed to the right. The professor wants to predict the maximum score and understand the distribution of the sample maximum. She simulates the distribution of the maximum of the test for 37 different tests (with n=5) The histogram to the right shows a simulated sampling distribution of the sample maximum from these tests. Complete parts a) and b) below. a) Would a Normal model be a useful model for this sampling distribution? Explain. A. No. The sampling distribution of the maximum is skewed to the right, so a Normal model would not be useful for this sampling distribution OB. No. The sampling distribution of the maximum is symmetric and unimodal, so a Normal model would not be useful for this sampling distribution OC. Yes. The sampling distribution of the maximum is symmetric and unimodal, so a Normal model would be useful for this sampling distribution OD. Yes. The sampling distribution of the maximum is skewed to the right, so a Normal model would be useful for this sampling distribution b) The mean of this distribution is 46.2 and the SD is 3.5. Would you expect about 68% of the samples to have their maximums within 3.5 of 46.27 Why or why not? OA. Yes. The 68-95-09.7 Rule is based on the Normal distribution OB. No. The values show too much variation to apply the 68-95-99.7 Rule, C. Yes. The values show too little variation to apply the 68-95-99.7 Rule. OD. No. The 68-95-99.7 Rule is based on the Normal distribution Frequency 2 4 8 4 8 40 45 50 Max Se E
Transcribed Image Text:K The distribution of scores on a test for a particular class is skewed to the right. The professor wants to predict the maximum score and understand the distribution of the sample maximum. She simulates the distribution of the maximum of the test for 37 different tests (with n=5) The histogram to the right shows a simulated sampling distribution of the sample maximum from these tests. Complete parts a) and b) below. a) Would a Normal model be a useful model for this sampling distribution? Explain. A. No. The sampling distribution of the maximum is skewed to the right, so a Normal model would not be useful for this sampling distribution OB. No. The sampling distribution of the maximum is symmetric and unimodal, so a Normal model would not be useful for this sampling distribution OC. Yes. The sampling distribution of the maximum is symmetric and unimodal, so a Normal model would be useful for this sampling distribution OD. Yes. The sampling distribution of the maximum is skewed to the right, so a Normal model would be useful for this sampling distribution b) The mean of this distribution is 46.2 and the SD is 3.5. Would you expect about 68% of the samples to have their maximums within 3.5 of 46.27 Why or why not? OA. Yes. The 68-95-09.7 Rule is based on the Normal distribution OB. No. The values show too much variation to apply the 68-95-99.7 Rule, C. Yes. The values show too little variation to apply the 68-95-99.7 Rule. OD. No. The 68-95-99.7 Rule is based on the Normal distribution Frequency 2 4 8 4 8 40 45 50 Max Se E
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