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The distances in feet of the 51 home runs hit by Andrew Jones in 2005 are the following: 420 400 360 382 383 395 380 416 390 340 360 370 374 408 415 432 420 359 419 411 423 375 432 373 350 410 418 390 340 380 370 390 434 395 379 407 393 385 416 420 440 354 405 452 379 380 380 390 390 425 427

The distances in feet of the 51 home runs hit by Andrew Jones in 2005 are the following: 420 400 360 382 383 395 380 416 390 340 360 370 374 408 415 432 420 359 419 411 423 375 432 373 350 410 418 390 340 380 370 390 434 395 379 407 393 385 416 420 440 354 405 452 379 380 380 390 390 425 427

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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The distances in feet of the 51 home runs hit by Andrew Jones in 2005 are the following: 382 383 395 380 416 390 420 400 340 360 370 374 408 359 419 418 415 432 420 432 373 350 390 340 380 375 390 434 395 379 440 354 405 370 416 420 390 425 427 393 385 379 380 380 390 360 423 410 407 452 The minimum equals 340 and the maximum is 452; thus the range is 452-340 = 112. There are a number of possibilities for k. So that each member of your class gets the same result, take k = 12 and class intervals each with length 10. That is. (12)(10) = 120 > 112. We start with 339.5 and accordingly end at 459.5. Section 3.1 Descriptive Statistics and EDA 111 (a) Construct a stem-and-leaf diagram with stems of 34, 35, 45. (b) Construct a frequency table. (c) Plot the relative frequency histogram. (d) Draw a box-and-whisker diagram. (e) Computex and s. (1) Compute i and s2 of the grouped data. A
Transcribed Image Text:The distances in feet of the 51 home runs hit by Andrew Jones in 2005 are the following: 382 383 395 380 416 390 420 400 340 360 370 374 408 359 419 418 415 432 420 432 373 350 390 340 380 375 390 434 395 379 440 354 405 370 416 420 390 425 427 393 385 379 380 380 390 360 423 410 407 452 The minimum equals 340 and the maximum is 452; thus the range is 452-340 = 112. There are a number of possibilities for k. So that each member of your class gets the same result, take k = 12 and class intervals each with length 10. That is. (12)(10) = 120 > 112. We start with 339.5 and accordingly end at 459.5. Section 3.1 Descriptive Statistics and EDA 111 (a) Construct a stem-and-leaf diagram with stems of 34, 35, 45. (b) Construct a frequency table. (c) Plot the relative frequency histogram. (d) Draw a box-and-whisker diagram. (e) Computex and s. (1) Compute i and s2 of the grouped data. A
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