The distance travelled by a particle in timet is given by s= (2-5 m/s )t. Find (a) the average speed of the particle during the time 0 to 5.0 s, and (b) the instantaneous speed at t = 5.0 s.
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![The distance travelled by a particle in timet is given
by s= (2-5 m/s )t. Find (a) the average speed of the
particle during the time 0 to 5.0 s, and (b) the
instantaneous speed at t = 5°0 s.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3558de00-c934-479f-bcb8-2ebd8d22a10b%2F24fc9d99-d275-4cd6-ad7b-5e3bb9388d30%2Fem8r5ik_processed.jpeg&w=3840&q=75)
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- A boy runs for 23 seconds. During the first 10 seconds, his minimum speed is 2.2 m/s, while his maximum speed is 3.1 m/s. During the remaining time, his minimum speed is 3.1 m/s, while his maximum speed is 4.7 m/s. calculate the maximum (least upper bound) on the distance that he runs, in meters.Piolo's car is traveling initially at 20k(m)/(h). What is its final velocity if he accelerates the car to 3.3k(m)/(h^(2)) for 3h ?The velocity of a particle traveling in a straight line is given by v = (6t – 3t²) m/s, where t is in seconds. If s = 0 when t = 0, determine the particle's deceleration and position when t = 5 s. How far has the particle traveled during the t = 5 s time interval, and what is its average speed? I need a clear answer by hand, not by keyboard | dybala