The distance between consecutive peaks of a transverse wave is 1.45m. Eight peaks pass by you in 13.7s. a. How fast is this wave travelling? b. Could this be a sound wave? Explain your reasoning.
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- A 2.25-mm-long pipe has one end open. Among its possible standing-wave frequencies is 345 HzHz; the next higher frequency is 483 HzHz. A. Find the fundamental frequency. B. Find the sound speedA. he sound intensity level at a certain location is 32 dB (like during a quiet test time). What is the sound intensity at this location? 3.2 × 10-6 W/m2 6.9 × 10-10 W/m2 5.6 × 10-7 W/m2 3.8 × 10-5 W/m2 1.6 × 10-9 W/m2 2.4 × 10-8 W/m2 B. A sound of 60 dB is __________. 8 times as intense as a sound of 40 dB 1.5 times as intense as a sound of 40 dB 2 times as intense as a sound of 40 dB 4 times as intense as a sound of 40 dB 1,000 times as intense as a sound of 40 dB 10 times as intense as a sound of 40 dB 20 times as intense as a sound of 40 dB 100 times as intense as a sound of 40 dB 16 times as intense as a sound of 40 dB C. A sound of 60 dB is __________. 8 times as intense as a sound of 20 dB 4 times as intense as a sound of 20 dB 1,000 times as intense as a sound of 20 dB…As discussed in the chapter, many species of bats find flying insects by emitting pulses of ultrasound and listening for the reflections. This technique is called echolocation. Bats possess several adaptations that allow them to echolocate very effectively. Some bats have specially shaped noses that focus ultrasound echolocation pulses in the forward direction. Why is this useful?A. Increasing intensity reduces the time delay for a reflected pulse.B. The energy of the pulse is concentrated in a smaller area, so the intensity is larger; reflected pulses will have a larger intensity as well.C. Increasing intensity allows the bat to use a lower frequency and still have the same spatial resolution.
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- A.) I start with a bar 1.82 meters long. How long must I make a second bar to be a perfect fifth above the first? B.) A vibrating bar has a fundamental frequency of 423 Hz. Find the frequency of the 3rd overtone and bring it down by octaves until you are in the octave starting with the fundamental. What frequency is this? Note, 2.76f is the first overtone.A string is fixed at both ends. The mass of the string is 0.0010 kg and the length is 4 m. The string is under a tension of 180 N. The string is driven by a variable frequency source to produce standing waves on the string. Find the wavelengths and frequencies of the first four modes of standing waves. a. A1 = fi = Hz b. A2 = m f2 = Hz c. A3 = m f3 Hz %3D d. X4 = m fa = Hz60. What is the length of an open end air column that would resonate in the first harmonic at 262 Hz when the speed of sound is 345 m/s? A. .33 metersB. 1.32 metersC. .77 metersD. .66 meters
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