The distance a person can walk in time t is given by d = vt where d is measured in miles and t is measured in hours. a) Find the average velocity from t = 1 to t = 4 hours. b) Estimate the person's velocity at t = 4 hours.

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**Chapter 2 - The Derivative Function**

### Problem 1:
The distance a person can walk in time \( t \) is given by \( d = \sqrt{t} \), where \( d \) is measured in miles and \( t \) is measured in hours.

a) **Find the average velocity** from \( t = 1 \) to \( t = 4 \) hours.

b) **Estimate the person's velocity** at \( t = 4 \) hours.

### Problem 2:
A ball is dropped from a tall building and \( d \) is the number of feet it falls in \( t \) seconds. The following table shows some of the values of \( t \) and \( d \).

\[
\begin{array}{|c|c|c|c|c|c|}
\hline
t \, (\text{sec}) & 0 & 1 & 2 & 3 & 4 & 5 \\
\hline
d \, (\text{ft}) & 0 & 15.07 & 57.90 & 127.03 & 201.76 & 333.00 \\
\hline
\end{array}
\]

a) **Plot the six data points.** Label the axes and indicate the units that are being used.

b) **Explain why the slope of any secant line on the graph is a measure of velocity.**

c) **Make three estimates** of the velocity of the falling ball at \( t = 2 \) seconds.

### Explanation:
- **Secant Line Slope**: The slope of a secant line between two points on a distance-time graph represents the average velocity over that time interval.
- **Velocity Estimation**: By choosing points around \( t = 2 \) seconds, you can approximate the instantaneous velocity as the slope of the tangent at that point.

This exercise explores concepts of average vs. instantaneous velocity using basic calculus and physics principles.
Transcribed Image Text:**Chapter 2 - The Derivative Function** ### Problem 1: The distance a person can walk in time \( t \) is given by \( d = \sqrt{t} \), where \( d \) is measured in miles and \( t \) is measured in hours. a) **Find the average velocity** from \( t = 1 \) to \( t = 4 \) hours. b) **Estimate the person's velocity** at \( t = 4 \) hours. ### Problem 2: A ball is dropped from a tall building and \( d \) is the number of feet it falls in \( t \) seconds. The following table shows some of the values of \( t \) and \( d \). \[ \begin{array}{|c|c|c|c|c|c|} \hline t \, (\text{sec}) & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline d \, (\text{ft}) & 0 & 15.07 & 57.90 & 127.03 & 201.76 & 333.00 \\ \hline \end{array} \] a) **Plot the six data points.** Label the axes and indicate the units that are being used. b) **Explain why the slope of any secant line on the graph is a measure of velocity.** c) **Make three estimates** of the velocity of the falling ball at \( t = 2 \) seconds. ### Explanation: - **Secant Line Slope**: The slope of a secant line between two points on a distance-time graph represents the average velocity over that time interval. - **Velocity Estimation**: By choosing points around \( t = 2 \) seconds, you can approximate the instantaneous velocity as the slope of the tangent at that point. This exercise explores concepts of average vs. instantaneous velocity using basic calculus and physics principles.
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