The displacement vectors A and B shown in the figure below both have magnitudes of 3.70 m. The direction of vector A is0 = 22.0⁰.BL0(a) Find A + B graphically.magnitude 6.14direction56.03(b) Find A - B graphically.magnitude4.14direction-33.996(c) Find BA graphically.magnitudedirectionmo counterclockwise from the +x axismo counterclockwise from the +x axis7.263XYour response differs from the correct answer by more than 10%. Double check your calculations. m79.01X counterclockwise from the +x axis(d) Find A - 2B graphically.8.31XmagnitudeYour response differs from the correct answer by more than 10%. Double check your calculations. mX ° counterclockwise from the +x axisdirection79.01

Given, Two displacement vector A→ and B→ , both having magnitude of 3.70 m. The direction of vector…

Answered: The displacement vectors A and B shown…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The displacement vectors A and B shown in the figure below both have magnitudes of 3.70 m. The direction of vector A is
0 = 22.0⁰.
B
L
0
(a) Find A + B graphically.
magnitude 6.14
direction
56.03
(b) Find A - B graphically.
magnitude
4.14
direction
-33.996
(c) Find BA graphically.
magnitude
direction
m
o counterclockwise from the +x axis
m
o counterclockwise from the +x axis
7.263
X
Your response differs from the correct answer by more than 10%. Double check your calculations. m
79.01
X counterclockwise from the +x axis
(d) Find A - 2B graphically.
8.31
X
magnitude
Your response differs from the correct answer by more than 10%. Double check your calculations. m
X ° counterclockwise from the +x axis
direction
79.01

Expert Solution

Step 1

Given,

Two displacement vector $\vec{A} a n d \vec{B}, b o t h h a v i n g m a g n i t u d e o f 3.70 m . T h e d i r e c t i o n o f v e c t o r \vec{A} i s θ = 22 ° .$

$S o, v e c t o r \vec{A} = 3.70 m \cos 22.0 ° \hat{i} + 3.70 m \sin 22.0 ° \hat{j} = 3.43 m \hat{i} + 1.39 m \hat{j} v e c t o r \vec{B} = 3.70 m \cos 90.0 ° \hat{i} + 3.70 m \sin 90.0 ° \hat{j} = 0 m \hat{i} + 3.70 m \hat{j}$

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