**Educational Website Transcription:**---### Rotational Motion Problem**Problem Description:**The disk has an angular acceleration \(\alpha = 7 \, \text{rad/s}^2\) and angular velocity \(\omega = 3 \, \text{rad/s}\) at the instant shown. It does not slip at point \(A\).**Figure 1:**The figure illustrates a disk with a radius of \(0.5 \, \text{m}\) rotating about a fixed axis through point \(A\). The disk is positioned such that the line \(AC\) is at a \(45^\circ\) angle with the vertical line through \(A\). The angular velocity \(\omega\) is directed upward, and the angular acceleration \(\alpha\) acts counterclockwise.**Part A:**Determine the magnitude of the acceleration of point \(C\).- Express your answer to three significant figures and include the appropriate units.- Input format: \(a = \_\_\_\_ \, \text{Units}\)**Part B:**Determine the direction of the acceleration of point \(C\).- Express your answer using three significant figures.- Input format: \(\theta = \_\_\_\_^\circ\), measured counterclockwise from the negative x-axis. ---**Diagram Explanation:**The disk is shown edge-on with its center marked. The radius extends from the center \(O\) to point \(C\) at a \(45^\circ\) angle. \(A\) is the point on the x-axis where the disk does not slip. Angular velocity \(\omega\) is labeled with a curved arrow at the top of the disk indicating upward direction, and angular acceleration \(\alpha\) is also marked, suggesting anti-clockwise rotation. This setup is typical for analyzing rotational dynamics and understanding how linear acceleration at a point on a rotating body is determined.

Answered: The disk has an angular acceleration a…

The disk has an angular acceleration a = 7 rad/s² and angular velocity w = 3 rad/s at the instant shown. It does not slip at A. (Figure 1)

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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