The discharge of industrial wastewater into riversaffects water quality. To assess the effect of a particularpower plant on water quality, 24 water specimens weretaken 16 km upstream and 4 km downstream of the plant.Alkalinity (mg/L) was determined for each specimen, re-sulting in the summary quantities in the accompanyingtable. Do the data suggest that the true mean alkalinity ishigher downstream than upstream by more than 50 mg/L?Use a .05 significance level.StandardLocationMeanDeviationUpstream2475.91.83Downstream24183.61.70

Answered: The discharge of industrial wastewater…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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In each situation below, calculate the standardized score (or z-score) for the value x. A USE SALT (a) Mean u = 0, standard deviationo = 1, value x = 1.3. %3D z = (b) Мean u 11, standard deviation o = 6, value x = 5. %3D Z = (с) Меan и 3D 15, standard deviation o = 5, value x = 0. = Z (d) Mean u = -10, standard deviation o = 5, value x = -20. Z =
Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 50 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that ? = 7.20 ml/kg for the distribution of blood plasma.
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An investigation of the properties of bricks used to line aluminum smelter pots was published in an article. Six different commercial bricks were evaluated. The life span of a smelter pot depends on the porosity of the brick lining (the less porosity, the longer the life span); consequently, the researchers measured the apparent porosity of each brick specimen, as well as the mean pore diameter of each brick. See the table. Apparent Porosity (y). Mean Pore Diameter (x). Click the icon to view the table. Data table Mean Pore Diameter Apparent Porosity (%) (micrometers) Brick Interpret the y-intercept of the line. Choose the correct answer below. 18.7 12.0 В 18.3 9.8 O A. The y-intercept is Bo- This value has no meaning because 0 is not in the observed range of the independent variable mean pore diameter. 16.3 7.3 6.9 5.4 O B. The y-intercept is Bo: For each unit increase in mean pore diameter, the mean porosity is estimated to increase by B0- 17.2 10.9 O C. There is not enough…
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researchers wanted to determine if carpeted rooms contained more baterica than uncapted rooms. to determine the amount of bacterica in a room reseachers pumpled the air from the room over a petri dish at the rate of 1 cubic foot per minute for eight carpeted rooms and eight uncaprted rooms. colonies of baterica were alled to form in 16 petri dishes. the results shown below are the baterica counta per cubic foot mean standard deviation sample size capeted room 11.2 2.6774 8 uncapted room 9.7875 3.21 8 you want ti test using sigificance level of 0.01 whether the mean bactiria count is high for carpeted rooms than for uncapteed rooms. test whether the mean bacteria count is high for carpeted rooms thatn uncarpeted rooms. show all steps using the p value method. what is Ho and H1? what is the test statsic and p value? what conclusion can be made?
7. Did plant height of the Alpine ecotype of cinquefoil vary between gardens? Provide justification for your answer including appropriate screenshots of text output and figures from R. The height of the Alpine ecotype cinquefoil does vary. Week 1 Assignment: Characterizing Populations > Ichistan; uchstan # Stanford garden [1] 25.78633 [1] 31.30598 Ich math; ucmath # Mather garden [1] 41.35308 [1] 48.65359 >chtimb; ultimb # Timberline garden [1] 23.81529 [1] 29.17042 Environment History Connections Tutorial Import Dataset ▾ 61 MiB List▾ Global Environment n.stan n. timb s.math 26L 28L 9.61125358120879 s.stan 6.70010332870954 s.timb 6.78079688157715 $1 17.3924278891305 $2 6 $3 97 54 $5 30.15 53 uc1.math uc1.stan ucl. timb x y1 y2 уз Functions 48.6535875829896 31.3059780687354 29.170424087752 ... num [1:141] 20 20.2 20.5 20.8 21 num [1:141] 1.98e-10 6.70e-10 2.19e... num [1:141] 1.86e-45 1.40e-44 1.04e... num [1:141] 8.29e-07 2.19e-06 5.55e... Height in cm 10 20 30 40 50 60 60 Mather…
2. The level of dissolved oxygen in a river is an important indicator of the water's ability to support aquatic life. You collect water samples at 15 randomly chosen locations along a stream and measure the dissolved oxygen. Here are your results in milligrams per liter. 4.53 5.04 3.29 5.23 4.13 5.50 4.83 4.40 5.42 6.38 4.01 4.66 2.87 5.73 5.55 Construct and interpret a 95% confidence interval to estimate the mean dissolved oxygen level in the stream.
Periodically, the county Water Department tests the drinking water of homeowners for contaminants such as lead and copper. The lead and copper levels in water specimens collected in 1998 for a sample of 10 residents of a subdevelopement of the county are shown below. lead (μμg/L) copper (mg/L) 4.4 0.643 2.4 0.57 1.5 0.46 2.6 0.895 5.9 0.2 3.4 0.54 3.8 0.245 1.6 0.583 5.7 0.769 1.7 0.215 (a) Construct a 9999% confidence interval for the mean lead level in water specimans of the subdevelopment. ≤μ≤
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Trace metals in drinking water affect the flavor and an unusually high concentration can pose a health hazard. Ten pairs of data were taken measuring zinc concentration in bottom water and surface water. Bottom 0.430 0.266 0.567 0.531 0.707 0.716 0.651 0.589 0.469 0.723 Surface 0.415 0.238 0.390 0.410 0.605 0.609 0.632 0.523 0.411 0.612 Does the data suggest that the true average concentration in the bottom water is different than that of surface water? Note: You can assume that the conditions for inference are met.
Determine the point of estimate of the population mean and margin of error from the given information: Lower Bound: 5 Upper Bound: 23 Question 4 options: x¯= 15 E = 10 x¯= 12 E = 9 x¯= 13.5 E = 9 x¯= 14 E = 9

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