The directional derivative of f(x, y) = cos(x²y³ ) in the direction of the vecto v = 3i + 4j is Du f(r, y) = -zy(12z+6y) -sin(z²y³) O Du f(z, y) = -sin(2y³) – sin(32²y²) O Du f(x, y) = –3 sin(2ry³) – 4 sin(3z²y} ) %3D O Du f(x, y) = –xyʻ(12x + 6y) sin(x²y³)
The directional derivative of f(x, y) = cos(x²y³ ) in the direction of the vecto v = 3i + 4j is Du f(r, y) = -zy(12z+6y) -sin(z²y³) O Du f(z, y) = -sin(2y³) – sin(32²y²) O Du f(x, y) = –3 sin(2ry³) – 4 sin(3z²y} ) %3D O Du f(x, y) = –xyʻ(12x + 6y) sin(x²y³)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![The directional derivative of f(x, y) = cos(x²y°) in the direction of the vector
v = 3i + 4j is
- xy (12r+6y)
Du f(x, y)
sin(x²y³)
O Du f(a, y) = -sin(2ry) – sin(32²y²)
O Du f(x, y) = -3 sin(2ry³) – 4 sin(3a²y²)
O Du f(x, y) = -xy²(12x + 6y) sin(æ² y³ )](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F42955b1a-fea1-4488-988d-57b5eba2380f%2F9afe2bc8-3b91-420b-ab93-3ad1cb312039%2Foifqg4_processed.png&w=3840&q=75)
Transcribed Image Text:The directional derivative of f(x, y) = cos(x²y°) in the direction of the vector
v = 3i + 4j is
- xy (12r+6y)
Du f(x, y)
sin(x²y³)
O Du f(a, y) = -sin(2ry) – sin(32²y²)
O Du f(x, y) = -3 sin(2ry³) – 4 sin(3a²y²)
O Du f(x, y) = -xy²(12x + 6y) sin(æ² y³ )
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