The differential equation for the velocity "v" of a falling mass "m" subjected to air resistance proportional to the square of the instantaneous velocity is m -= mg - kv², where k>0 dv dt Is a constant of proportionality. The positive direction is upward. (a) Solve the equation subject to the initial condition v(0) = v₁. (b) Use the solution in part (a) to determine the limiting, or terminal velocity of the mass. (c) If the distance "s" measured from the point where the mass was released from the ground, is related to velocity v by ds = v(t), find dt an explicit expression for s(t) if s(0) = 0.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The differential equation for the velocity "v" of a falling mass "m"
subjected to air resistance proportional to the square of the
instantaneous velocity is m- = mg -kv², where k > 0
dv
dt
Is a constant of proportionality. The positive direction is upward.
(a) Solve the equation subject to the initial condition v(0) = V₁.
(b) Use the solution in part (a) to determine the limiting, or
terminal velocity of the mass.
(c) If the distance "s" measured from the point where the mass was
released from the ground, is related to velocity v by
ds
= v(t), find
dt
an explicit expression for s(t) if s(0) = 0.
=
Transcribed Image Text:The differential equation for the velocity "v" of a falling mass "m" subjected to air resistance proportional to the square of the instantaneous velocity is m- = mg -kv², where k > 0 dv dt Is a constant of proportionality. The positive direction is upward. (a) Solve the equation subject to the initial condition v(0) = V₁. (b) Use the solution in part (a) to determine the limiting, or terminal velocity of the mass. (c) If the distance "s" measured from the point where the mass was released from the ground, is related to velocity v by ds = v(t), find dt an explicit expression for s(t) if s(0) = 0. =
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