The differential equation - 7-17 - 9y = 0 has characteristic equation = 0 help (formulas) with roots Note: Enter the roots as a comma separated list. Therefore there are three fundamental solutions help (formulas) Note: Enter the solutions as a comma separated list. Use these to solve the initial value problem y(x) d³y dx³ help (numbers) ¸ď²y dy 17. dx dx² 7. - 9y = 0, y(0) = -2, help (formulas) dy dx -(0) -9, == d²y 22 (0) = 7 10 dx²

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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2.3.6. Ordinary Differential Equations 

The differential equation 

\[ \frac{d^3y}{dx^3} - 7 \frac{d^2y}{dx^2} - 17 \frac{dy}{dx} - 9y = 0 \]

has characteristic equation

\[
\boxed{\phantom{\text{solution}}}=0 \quad \text{help (formulas)}
\]

with roots 

\[
\boxed{\phantom{\text{roots}}} \quad \text{help (numbers)}
\]

*Note: Enter the roots as a comma-separated list.*

Therefore, there are three fundamental solutions

\[
\boxed{\phantom{\text{solutions}}} \quad \text{help (formulas)}
\]

*Note: Enter the solutions as a comma-separated list.*

Use these to solve the initial value problem

\[
\frac{d^3y}{dx^3} - 7 \frac{d^2y}{dx^2} - 17 \frac{dy}{dx} - 9y = 0, \quad y(0) = -2, \quad \frac{dy}{dx}(0) = -9, \quad \frac{d^2y}{dx^2}(0) = 7
\]

\[ y(x) = \boxed{\phantom{\text{y(x)}}} \quad \text{help (formulas)} \]
Transcribed Image Text:The differential equation \[ \frac{d^3y}{dx^3} - 7 \frac{d^2y}{dx^2} - 17 \frac{dy}{dx} - 9y = 0 \] has characteristic equation \[ \boxed{\phantom{\text{solution}}}=0 \quad \text{help (formulas)} \] with roots \[ \boxed{\phantom{\text{roots}}} \quad \text{help (numbers)} \] *Note: Enter the roots as a comma-separated list.* Therefore, there are three fundamental solutions \[ \boxed{\phantom{\text{solutions}}} \quad \text{help (formulas)} \] *Note: Enter the solutions as a comma-separated list.* Use these to solve the initial value problem \[ \frac{d^3y}{dx^3} - 7 \frac{d^2y}{dx^2} - 17 \frac{dy}{dx} - 9y = 0, \quad y(0) = -2, \quad \frac{dy}{dx}(0) = -9, \quad \frac{d^2y}{dx^2}(0) = 7 \] \[ y(x) = \boxed{\phantom{\text{y(x)}}} \quad \text{help (formulas)} \]
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