The difference 8 (1) – 8 (0.5) equals the change in the ball's height (in feet) between time 0.5 and time 1. The difference 1 – 0.5 equals the amount of time elapsed (in seconds) on that same time interval, 0.5
The difference 8 (1) – 8 (0.5) equals the change in the ball's height (in feet) between time 0.5 and time 1. The difference 1 – 0.5 equals the amount of time elapsed (in seconds) on that same time interval, 0.5
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![The difference
8 (1) – 8 (0.5)
equals the change in the ball's height (in feet) between time 0.5 and time 1.
The difference
1 – 0.5
equals the amount of time elapsed (in seconds) on that same time interval, 0.5 <t< 1.
Therefore, the quotient (fraction) expression
s(1)–s(0.5)
1-0.5
has what units?
O feet per second
O feet
seconds](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fac5283e3-f6aa-49e5-88cf-4d2e121a7698%2Fe6ea13d8-9e8f-4931-938a-863570c8dd00%2Flkhersd_processed.png&w=3840&q=75)
Transcribed Image Text:The difference
8 (1) – 8 (0.5)
equals the change in the ball's height (in feet) between time 0.5 and time 1.
The difference
1 – 0.5
equals the amount of time elapsed (in seconds) on that same time interval, 0.5 <t< 1.
Therefore, the quotient (fraction) expression
s(1)–s(0.5)
1-0.5
has what units?
O feet per second
O feet
seconds
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