The dice are rolled twice. Event A means that the sum of the mesh numbers is 7 and event B means that the face number of the first die is odd. What is the event A∪B probability?
The dice are rolled twice. Event
A means that the sum of the mesh numbers is 7 and event B
means that the face number of the first die is odd. What is the event A∪B
probability? Hint: tabulate all elementary cases. Give the answer as a decimal with two decimal places. Remember the correct decimal separator.
When two dice are rolled, the sample space consists of the events
S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2,1), . . . . . . . . , (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
So, |S| = 36.
Then favourable events of A are SA = {(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)}
So, |SA| = 6
Favourable events of B are SB = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)}
So, |SB| = 18.
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