The diameter of the moon is about 3500 km. Write the diameter of the moon in scientific notation. O A. 3.5 x 102 km O B. 35 x 102 km C. 3.5 x 103 km D. 0.35 x 104 km
The diameter of the moon is about 3500 km. Write the diameter of the moon in scientific notation. O A. 3.5 x 102 km O B. 35 x 102 km C. 3.5 x 103 km D. 0.35 x 104 km
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![**Question: Scientific Notation of the Moon's Diameter**
**Context:**
The diameter of the moon is about 3,500 km. Write the diameter of the moon in scientific notation.
**Options:**
- A. \(3.5 \times 10^2 \text{ km}\)
- B. \(35 \times 10^2 \text{ km}\)
- C. \(3.5 \times 10^3 \text{ km}\)
- D. \(0.35 \times 10^4 \text{ km}\)
To solve this, we need to convert 3,500 km into scientific notation. Scientific notation expresses numbers as a product of a coefficient (between 1 and 10) and a power of 10.
Let's break down the conversion:
- 3,500 can be rewritten as \(3.5 \times 1,000\)
- And 1,000 is \(10^3\) (since 1,000 has three zeros)
Thus, 3,500 can be expressed as:
\[3.5 \times 10^3 \text{ km}\]
**Correct Option:**
- C. \(3.5 \times 10^3 \text{ km}\)
**Explanation:**
The diameter of the moon in scientific notation is \(3.5 \times 10^3 \text{ km}\). The other options listed either misplace the decimal point or incorrectly represent the exponent in the scientific notation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F384bb2d8-4bfb-40a4-b5b5-cce563951ac9%2F195b3c2e-7920-4405-9d16-aa13eb6974b3%2Fscu2g4a_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question: Scientific Notation of the Moon's Diameter**
**Context:**
The diameter of the moon is about 3,500 km. Write the diameter of the moon in scientific notation.
**Options:**
- A. \(3.5 \times 10^2 \text{ km}\)
- B. \(35 \times 10^2 \text{ km}\)
- C. \(3.5 \times 10^3 \text{ km}\)
- D. \(0.35 \times 10^4 \text{ km}\)
To solve this, we need to convert 3,500 km into scientific notation. Scientific notation expresses numbers as a product of a coefficient (between 1 and 10) and a power of 10.
Let's break down the conversion:
- 3,500 can be rewritten as \(3.5 \times 1,000\)
- And 1,000 is \(10^3\) (since 1,000 has three zeros)
Thus, 3,500 can be expressed as:
\[3.5 \times 10^3 \text{ km}\]
**Correct Option:**
- C. \(3.5 \times 10^3 \text{ km}\)
**Explanation:**
The diameter of the moon in scientific notation is \(3.5 \times 10^3 \text{ km}\). The other options listed either misplace the decimal point or incorrectly represent the exponent in the scientific notation.
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