The diameter of holes for a cable harness is known to have a normal distribution with o = 0.03 inches. A random sample of size 12 yields an average diameter of 1.5045 inches. Find a 95% two-sided confidence interval on the mean hole diameter. Round the answers to 4 decimal places. sHs i
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A: Given : Claim : The mean age of graduate students at a University is at most 31 years .
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- In the entire population of a certain type of tree, the mean height of the trees is μ = 168.8 ft and the standard deviation is σ = 43.6 ft. You collect a random sample of n=22 trees. The distribution of these sample means is shown below. Each tick mark on the horizontal axis is a distance of one more standard error. Complete the indicated boxes, correct to two decimal places. mean of distribution=168.8 standard error=9.30 Note: The left box is 2 standard errors below the mean. The middle box is the mean. The right box is 2 standard errors above the mean.A population has a mean μ = 73 and a standard deviation o = 28. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 257. Hx ox (Simplify your answer.) (Type an integer or decimal rounded to three decimal places as needed.)A recent personalized information sheet from your wireless phone carrier claims that the mean duration of all your phone calls was μ=3.1 minutes with a standard deviation of σ=2.4 minutes. From a random sample of n=50 calls, your parents computed a sample mean of x=4.1 minutes and a sample standard deviation of s=3.2 minutes. Complete parts a through e below. a. Sketch the population distribution for the duration of your phone calls. What are its mean and standard deviation? b. What are the mean and standard deviation of the data distribution? c. Find the mean and standard deviation of the sampling distribution of the sample mean. d. Is the sample mean of 4.1 minutes unusually high? Find its z-score and comment. e. Your parents told you that they will kick you off the plan when they find a sample mean larger than 4.2 minutes. How likely is this to happen? P(x>4.2 minutes)= ?
- In a population of a certain species of newt, the mean length of the newts is μ= 63 inches and the standard deviation is σ= 3.4 inches. You collect a random sample of n=16 newts. The bell curve below represents the distribution of these sample means. The scale on the horizontal axis is the standard error of the sampling distribution. Complete the indicated boxes, correct to two decimal places. mean of distribution= standard error= Note: The left box is 2 standard errors below the mean. The middle box is the mean. The right box is 2 standard errors above the mean.A random sample of 15 exam scores showed a standard deviation of 6.0 points. Find the 95 percent confidence interval for the population standard deviation. Use Appendix E to obtain the values of χ2LχL2 and χ2UχU2 . (Round your answers to 2 decimal places.) The 95% confidence interval is from ______ to __________ .Calcium levels in people are normally distributed with a mean of 9.7 mgdL and a standard deviation of 0.5 mgdL . Individuals with calcium levels in the bottom 10% of the population are considered to have low calcium levels. Find the calcium level that is the borderline between low calcium levels and those not considered low. Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
- The pulse rates of 177 randomly selected adult males vary from a low of 35 bpm to a high of 103 bpm. Find the minimum sample size required to estimate the mean pulse rate of adult males. Assume that we want 95% confidence that the sample mean is within 2 bpm of the population mean. Complete parts (a) through (c) below. a. Find the sample size using the range rule of thumb to estimate 6. n3= (Round up to the nearest whole number as needed.) b. Assume that o = 11.9 bpm, based on the value s = 11.9 bpm from the sample of 177 male pulse rates. n=D (Round up to the nearest whole number as needed.) c. Compare the results from parts (a) and (b). Which result is likely to be better? The result from part (a) is larger than the result from part (b). The result from part (b) is likely to be better because it uses a better estimate of o.The random sample of n=75�=75 yielded a sample mean of x¯=26�¯=26.Assume that we know the population standard deviation is σ=30�=30. Step 2 of 3 : Calculate a 95% confidence interval for the population mean. Round your answers to 2 decimals places.Assume that a sample is used to estimate a population mean μμ. Find the margin of error that corresponds to a sample of size 16 with a mean of 68.3 and a standard deviation of 17.9 at a confidence level of 99%.Report the margin of error accurate to one decimal place because the sample statistics are presented with this accuracy.E=
- Assume that adults have IQ scores that are normally distributed with a mean of 100.4 and a standard deviation 23.2. Find the first quartile Q1, which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) The first quartile is: (Type an integer or decimal rounded to one decimal place as needed.)You measure 22 textbooks' weights, and find they have a mean weight of 53 ounces. Assume the population standard deviation is 7.9 ounces. Based on this, construct a 90 % confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places εμε