The diameter of holes for a cable harness is known to have a normal distribution with o = 0.03 inches. A random sample of size 12 yields an average diameter of 1.5045 inches. Find a 95% two-sided confidence interval on the mean hole diameter. Round the answers to 4 decimal places. sHs i
Q: You measure 40 watermelons' weights, and find they have a mean weight of 32 ounces. Assume the…
A: Given mean weight of 32 ounces. and the population standard deviation is 12.2 ounces
Q: A population has a mean u = 155 and a standard deviation o =21. Find the mean and standard deviation…
A: Given : μ = 155 , σ= 21 and n= 50
Q: For a population with u = 34, a score of X = 31 corresponds to z = -1.00. The standard deviation for…
A:
Q: Use the given data to find the 95% confidence interval estimate of the population mean μ . Assume…
A: Given , Sample size , n = 14Mean , = 103.4Standard deviation , S = 14 We have to find the 95%…
Q: A sample of 52 obsorvation is drawn from a population with standard deviation 60. Find C so that the…
A: Consider that the mean and standard deviation of a random variable X are µ and σ, respectively.…
Q: ssume that a sample is used to estimate a population mean μμ. Find the 95% confidence interval for a…
A: It is given that the mean is 50.2 and the population standard deviation is 12.2.
Q: a. Using the test statistic approach, what conclusion should be reached about the null hypothesis?…
A: Given Hypothesis : a) This corresponds to two-tailed z-test (Population standard deviation are…
Q: The pulse rates of 140 randomly selected adult males vary from a low of 45 bpm to a high of 121 bpm.…
A: Answer Given confidence interval =99%Margin of error [E] =2Max value =121Min value =45
Q: Previous studies have suggested that human body temperature is normally distributed with a mean of…
A: It is given that human body temperature is normally distributed with mean of 98.6and standard…
Q: Use the given data to find the 95% confidence interval estiate of the population mean ?. Assume that…
A:
Q: If n = 22, ¯xx¯ = 44, and s = 11, construct a confidence interval at a 95% confidence level. Assume…
A: Obtain the 95% confidence interval for the population mean. The 95% confidence interval for the…
Q: items have a length less than 45 cm and 22.66% have a length greater than 49 cm. Find the values of…
A:
Q: 5. A random sample of 43 foreign language movies made since the year 2000 had a mean length of 112.5…
A: Here, the parent distribution from which the sample is taken is unknown and also, the population…
Q: If n = 22, ¯xx¯ = 30, and s = 9, construct a confidence interval at a 98% confidence level. Assume…
A: According to the provided information, n = 22, ¯x = 30 s = 9 degrees of freedom = n-1 = 22-1 = 21…
Q: To gauge their fear of going to a dentist, a random sample of adults completed the Modified Dental…
A: We have given that all scores on the modified dental anxiety scale is approximately…
Q: A researcher has reported the interquartile range of a data set. What might be the reason they chose…
A: Given that a researcher has reported the interquartile range of a data set. We have to choose the…
Q: During rush hour, the traffic speed on a busy highway is found to have mean 42 mph and standard…
A:
Q: Assume that a sample is used to estimate a population mean μμ. Find the margin of error that…
A: Solution: Given information: n= 13 Sample size x= 54.9 Sample mean s= 16.6 Sample standard…
Q: The pulse rates of 153 randomly selected adult males vary from a low of 43 bpm to a high of 107 bpm.…
A:
Q: For a confidence level of 80% with a sample size of 27, find the critical t value.
A: We have given that, Sample size (n) = 27 and confidence interval = 80% Then, We will find the…
Q: Assume that adults have IQ scores that are normally distributed with a mean of 103.6 and a standard…
A: We have given that, IQ scores are normally distributed with mean (mu) = 103.6 and standard…
Q: The pulse rates of 174 randomly selected adult males vary from a low of 41 bpm to a high of 117 bpm.…
A: From the provided information, The pulse rates of 174 randomly selected adult males vary from a low…
Q: In a random sample of eight people, the mean driving distance to work was 21.7 miles and the…
A: Given that : Sample size (n) = 8 Sample mean = Standard deviation (s) = 7.4 Confidence interval is…
Q: 1. The average weight of sugar in a medium-size bag is stated to be less than 10 kilograms. The…
A:
Q: The random sample yielded a sample mean of x¯=38.2�¯=38.2. Assume that we know the population…
A:
Q: Use the given data to find the 95% confidence interval estimate of the population mean μ. Assume…
A:
Q: Find the p-value. p-value = | (Round to three decimal places as needed.) Interpret the results of…
A:
Q: Out who contracted the flu to Show symptons was 4.14 days after exposure wit a Stundard deviation of…
A: Given information- Sample size, n = 286 Sample mean, x-bar = 4.14 days Standard deviation, s = 3.76…
Q: Assume that adults have IQ scores that are normally distributed with a mean of 95.1 and a standard…
A:
Q: Assume that adults have IQ scores that are normally distributed with a mean of 103.4 and a standard…
A:
Q: If n = 19, ¯xx¯ = 34, and s = 20, construct a confidence interval at a 95% confidence level. Assume…
A:
Q: Assume that adults have IQ scores that are normally distributed with mean of 98.7 and a standard…
A: Given X is normal Distributed with mean µ = 98.7 and standard deviation σ = 22.5 now will use…
Q: random sample of 81 automobiles traveling on a section of an interstate showed an average speed of…
A: Given that The speeds are normally distributed. Random sample size (n) = 81 Average speed (x¯) = 60…
Q: A sample of size 65 with = 71.9 and s = 16.6 is used to estimate a population mean u. Find the 90%…
A: The random variable X follows normal distribution. The sample size is 65. The sample mean is 71.9.…
Q: Assume that a sample is used to estimate a population mean μμ. Find the 90% confidence interval for…
A:
Q: The average American gets a haircut every 35 days. Is the average smaller for college students? The…
A: In this case, a test is conducted by an agency to see whether the average is less than 35. Here, the…
Q: Assume that adults have IQ scores that are normally distributed with a mean of 96.2and a standard…
A: Solution: Let X be the IQ score. From the given information, X follows normal distribution with mean…
Q: The shape of a given population distribution is normal with a mean of u = 85 and a standard…
A: Answer: from the given data, Mean μ = 85 Standard deviation σ = 6.5 The distribution is normal
Q: 1. The average weight of a jelly bean is known to be 1.10 grams. It's known to have a standard…
A: Statistical hypothesis testing is an important method in inferential statistics. It is used to test…
Q: Heights were measured for a fam sample 13 plar grown while being treated with a particular nutrient.…
A: Given Sample size n=15, sample mean x̄=50, sample standard deviations s=12 , population mean μ=42 ,…
Q: Consider random samples of size 45 from a population with proportion 0.35. Find the standard error…
A: Given information- Sample size, n = 45 Population proportion, p = 0.35 We have to find the standard…
Q: should increase when a new variable is manipulated. To test their claim, the research collects a…
A: Let be the population variance.Given that,Population variance Sample size Sample variance Assume…
Q: Use the given data to find the 95% confidence interval estimate of the population mean μ. Assume…
A:
Q: The mean
A: Given : Claim : The mean age of graduate students at a University is at most 31 years .
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
- In the entire population of a certain type of tree, the mean height of the trees is μ = 168.8 ft and the standard deviation is σ = 43.6 ft. You collect a random sample of n=22 trees. The distribution of these sample means is shown below. Each tick mark on the horizontal axis is a distance of one more standard error. Complete the indicated boxes, correct to two decimal places. mean of distribution=168.8 standard error=9.30 Note: The left box is 2 standard errors below the mean. The middle box is the mean. The right box is 2 standard errors above the mean.A population has a mean μ = 73 and a standard deviation o = 28. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 257. Hx ox (Simplify your answer.) (Type an integer or decimal rounded to three decimal places as needed.)A recent personalized information sheet from your wireless phone carrier claims that the mean duration of all your phone calls was μ=3.1 minutes with a standard deviation of σ=2.4 minutes. From a random sample of n=50 calls, your parents computed a sample mean of x=4.1 minutes and a sample standard deviation of s=3.2 minutes. Complete parts a through e below. a. Sketch the population distribution for the duration of your phone calls. What are its mean and standard deviation? b. What are the mean and standard deviation of the data distribution? c. Find the mean and standard deviation of the sampling distribution of the sample mean. d. Is the sample mean of 4.1 minutes unusually high? Find its z-score and comment. e. Your parents told you that they will kick you off the plan when they find a sample mean larger than 4.2 minutes. How likely is this to happen? P(x>4.2 minutes)= ?
- In a population of a certain species of newt, the mean length of the newts is μ= 63 inches and the standard deviation is σ= 3.4 inches. You collect a random sample of n=16 newts. The bell curve below represents the distribution of these sample means. The scale on the horizontal axis is the standard error of the sampling distribution. Complete the indicated boxes, correct to two decimal places. mean of distribution= standard error= Note: The left box is 2 standard errors below the mean. The middle box is the mean. The right box is 2 standard errors above the mean.A random sample of 15 exam scores showed a standard deviation of 6.0 points. Find the 95 percent confidence interval for the population standard deviation. Use Appendix E to obtain the values of χ2LχL2 and χ2UχU2 . (Round your answers to 2 decimal places.) The 95% confidence interval is from ______ to __________ .Calcium levels in people are normally distributed with a mean of 9.7 mgdL and a standard deviation of 0.5 mgdL . Individuals with calcium levels in the bottom 10% of the population are considered to have low calcium levels. Find the calcium level that is the borderline between low calcium levels and those not considered low. Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.
- The pulse rates of 177 randomly selected adult males vary from a low of 35 bpm to a high of 103 bpm. Find the minimum sample size required to estimate the mean pulse rate of adult males. Assume that we want 95% confidence that the sample mean is within 2 bpm of the population mean. Complete parts (a) through (c) below. a. Find the sample size using the range rule of thumb to estimate 6. n3= (Round up to the nearest whole number as needed.) b. Assume that o = 11.9 bpm, based on the value s = 11.9 bpm from the sample of 177 male pulse rates. n=D (Round up to the nearest whole number as needed.) c. Compare the results from parts (a) and (b). Which result is likely to be better? The result from part (a) is larger than the result from part (b). The result from part (b) is likely to be better because it uses a better estimate of o.The random sample of n=75�=75 yielded a sample mean of x¯=26�¯=26.Assume that we know the population standard deviation is σ=30�=30. Step 2 of 3 : Calculate a 95% confidence interval for the population mean. Round your answers to 2 decimals places.Assume that a sample is used to estimate a population mean μμ. Find the margin of error that corresponds to a sample of size 16 with a mean of 68.3 and a standard deviation of 17.9 at a confidence level of 99%.Report the margin of error accurate to one decimal place because the sample statistics are presented with this accuracy.E=
- Assume that adults have IQ scores that are normally distributed with a mean of 100.4 and a standard deviation 23.2. Find the first quartile Q1, which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) The first quartile is: (Type an integer or decimal rounded to one decimal place as needed.)You measure 22 textbooks' weights, and find they have a mean weight of 53 ounces. Assume the population standard deviation is 7.9 ounces. Based on this, construct a 90 % confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places εμε