Can you help and show all work ? The diameter of a copper wire is 0.082in. Suppose the maximum safe current it cancarry is 22.9A. At this current, what is the drift velocity of the electrons (inum(The number of electron carriers in1.0cm3of copper is8.5 × 1022 The problem involves determining the drift velocity of electrons in a copper wire. Here's the transcribed text:"The diameter of a copper wire is 0.082 inches. Suppose the maximum safe current it can carry is 22.9 A. At this current, what is the drift velocity of the electrons (in µm/s)?(The number of electron carriers in 1.0 cm³ of copper is \(8.5 \times 10^{22}\).)The calculated answer is input as 474.664. The accepted answer is 493.593 with a margin of error of +/- 1%."

Diameter, d = 0.082in = 0.00208 mCurrent, I = 22.9 ANumber density, n = 8.5×10²² /cm³ Drift velocity, v = ? Current equation in an conductor can be given as, I = neAvWhere, A is area of cross section. A = (πd²)/4= [π(0.00208 m)²]/4 = 3.397×10-6 m²Put values, Drift velocity is 493.593 μm/s

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Can you help and show all work ? The diameter of a copper wire is 0.082in. Suppose the maximum safe current it can carry is 22.9A. At this current, what is the drift velocity of the electrons (in um (The number of electron carriers in 1.0cm3 of copper is 8.5 × 1022

The problem involves determining the drift velocity of electrons in a copper wire. Here's the transcribed text:

"The diameter of a copper wire is 0.082 inches. Suppose the maximum safe current it can carry is 22.9 A. At this current, what is the drift velocity of the electrons (in µm/s)?

(The number of electron carriers in 1.0 cm³ of copper is \(8.5 \times 10^{22}\).)

The calculated answer is input as 474.664. The accepted answer is 493.593 with a margin of error of +/- 1%."

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