The diagram shows two rectangles ABCD and PQRS. AB = (2x + 5) cm, AD = (x + 3) cm, PQ = (x+4) cm and PS = x cm. (r+3) cm (2x+5)cm (x+4)cm For one value of x, the area of rectangle ABCD is 59 cm2 more than the area of rectangle PQRS. Show that x² +7x- 44 = 0.

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