The diagram shows the instant when a long slender bar of mass 4.8 kg and length 1.9 m is horizontal. At this instant the mass m= 7.4 kg has a vertical velocity of 3.5 m/s. If the pulley has negligible mass and all friction effects may be ignored, what is the magnitude of the reaction force on the bearing A?

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Plz this is my last chance plz gave me correct Soloution . This is not fair i already said u gave me correct Soloution u give me wrong soloution again plz give me correct Soloution and take a up
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The diagram shows the instant when a long slender bar of mass 4.8 kg and length 1.9 m
is horizontal. At this instant the mass m= 7.4 kg has a vertical velocity of 3.5 m/s.
If the pulley has negligible mass and all friction effects may be ignored, what is the
magnitude of the reaction force on the bearing A?
Answer: 50.5 N
Incorrect! Try again.
Transcribed Image Text:m The diagram shows the instant when a long slender bar of mass 4.8 kg and length 1.9 m is horizontal. At this instant the mass m= 7.4 kg has a vertical velocity of 3.5 m/s. If the pulley has negligible mass and all friction effects may be ignored, what is the magnitude of the reaction force on the bearing A? Answer: 50.5 N Incorrect! Try again.
48 ng
1.9m
דיר
35 m/s
2a
%3D
12
m,a=3(N-T]/_O
he anguler attefemation about the
porrt f the nad inthe antielockwise divection
the point A must have zem accelentim
subififtuting equation
a-
3N-37 = Mog -T-N
2.
Net force on the block my
T-mg o o
T mg
N< ( Mog + 2mg
3.
By sudifitating valu@ in equation ☺r
N- 381 (48+2134り
Net forle on the mod
hav
a- mg- Ra TートN
Net moment on the mad at mid point
N= 48.069 Newton L Answer
2, Reaction force on
2
As I mol? / about Cilb. of Rod)
Answer: 48.069 I
Incorrect! Try again.
Try again
Transcribed Image Text:48 ng 1.9m דיר 35 m/s 2a %3D 12 m,a=3(N-T]/_O he anguler attefemation about the porrt f the nad inthe antielockwise divection the point A must have zem accelentim subififtuting equation a- 3N-37 = Mog -T-N 2. Net force on the block my T-mg o o T mg N< ( Mog + 2mg 3. By sudifitating valu@ in equation ☺r N- 381 (48+2134り Net forle on the mod hav a- mg- Ra TートN Net moment on the mad at mid point N= 48.069 Newton L Answer 2, Reaction force on 2 As I mol? / about Cilb. of Rod) Answer: 48.069 I Incorrect! Try again. Try again
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