The diagram shows the instant when a long slender bar of mass 4.8 kg and length 1.9 m is horizontal. At this instant the mass m= 7.4 kg has a vertical velocity of 3.5 m/s. If the pulley has negligible mass and all friction effects may be ignored, what is the magnitude of the reaction force on the bearing A?
The diagram shows the instant when a long slender bar of mass 4.8 kg and length 1.9 m is horizontal. At this instant the mass m= 7.4 kg has a vertical velocity of 3.5 m/s. If the pulley has negligible mass and all friction effects may be ignored, what is the magnitude of the reaction force on the bearing A?
International Edition---engineering Mechanics: Statics, 4th Edition
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ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
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Chapter7: Dry Friction
Section: Chapter Questions
Problem 7.78P: The figure shows a steel bar being processed by a rolling mill. Given that P=80kN and r =0.016,...
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The diagram shows the instant when a long slender bar of mass 4.8 kg and length 1.9 m
is horizontal. At this instant the mass m= 7.4 kg has a vertical velocity of 3.5 m/s.
If the pulley has negligible mass and all friction effects may be ignored, what is the
magnitude of the reaction force on the bearing A?
Answer: 50.5 N
Incorrect! Try again.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf8db08f-d2ca-4eda-b514-ec6a6bb438ae%2F29089e88-fed2-41b8-85bc-e05e89036f58%2Fa2f49jr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:m
The diagram shows the instant when a long slender bar of mass 4.8 kg and length 1.9 m
is horizontal. At this instant the mass m= 7.4 kg has a vertical velocity of 3.5 m/s.
If the pulley has negligible mass and all friction effects may be ignored, what is the
magnitude of the reaction force on the bearing A?
Answer: 50.5 N
Incorrect! Try again.
![48 ng
1.9m
דיר
35 m/s
2a
%3D
12
m,a=3(N-T]/_O
he anguler attefemation about the
porrt f the nad inthe antielockwise divection
the point A must have zem accelentim
subififtuting equation
a-
3N-37 = Mog -T-N
2.
Net force on the block my
T-mg o o
T mg
N< ( Mog + 2mg
3.
By sudifitating valu@ in equation ☺r
N- 381 (48+2134り
Net forle on the mod
hav
a- mg- Ra TートN
Net moment on the mad at mid point
N= 48.069 Newton L Answer
2, Reaction force on
2
As I mol? / about Cilb. of Rod)
Answer: 48.069 I
Incorrect! Try again.
Try again](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf8db08f-d2ca-4eda-b514-ec6a6bb438ae%2F29089e88-fed2-41b8-85bc-e05e89036f58%2Fylo5t2b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:48 ng
1.9m
דיר
35 m/s
2a
%3D
12
m,a=3(N-T]/_O
he anguler attefemation about the
porrt f the nad inthe antielockwise divection
the point A must have zem accelentim
subififtuting equation
a-
3N-37 = Mog -T-N
2.
Net force on the block my
T-mg o o
T mg
N< ( Mog + 2mg
3.
By sudifitating valu@ in equation ☺r
N- 381 (48+2134り
Net forle on the mod
hav
a- mg- Ra TートN
Net moment on the mad at mid point
N= 48.069 Newton L Answer
2, Reaction force on
2
As I mol? / about Cilb. of Rod)
Answer: 48.069 I
Incorrect! Try again.
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