The derivatives of the function f(x) = cos(3x²) that follow are incorrect. What misconception occurs in each case? (a) Incorrect: f'(x) = (b) Incorrect: f'(x) = In the - sin(3x²). sin(3x²) (6x) (6).
The derivatives of the function f(x) = cos(3x²) that follow are incorrect. What misconception occurs in each case? (a) Incorrect: f'(x) = (b) Incorrect: f'(x) = In the - sin(3x²). sin(3x²) (6x) (6).
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Numbers 6 & 8 please
![6. Suppose you wish to diff
What is the fastest way to do this, and why?
7. The derivatives of the function f(x) = cos(3x²) that follow
are incorrect. What misconception occurs in each case?
(a) Incorrect: f'(x) = (- sinx) (3x2)+(cos x) (6x).
(b) Incorrect: f'(x) = sin(6x).
8. The derivatives of the function f(x) = cos(3x2) that follow
are incorrect. What misconception occurs in each case?
(a) Incorrect: f'(x) = sin(3x²).
(b) Incorrect: f'(x) = sin(3x²) (6x) (6).
9. In the proof that
1
dx
√1-x²
that sin(sin-¹ x) = x. It is also true that sin-¹ (sinx) = x
could we have started with that inequality instead? Why
|| = |
(x) + cos(x).
(sin ¹x) =
or why not?
10. Both of the following
and tan-1
I
we used the fact](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F27d35152-6917-4f16-a4e1-3cd886d8c64b%2F3f1bd3a8-74b4-4274-b001-44e35973e1e2%2Fd7ud6qm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. Suppose you wish to diff
What is the fastest way to do this, and why?
7. The derivatives of the function f(x) = cos(3x²) that follow
are incorrect. What misconception occurs in each case?
(a) Incorrect: f'(x) = (- sinx) (3x2)+(cos x) (6x).
(b) Incorrect: f'(x) = sin(6x).
8. The derivatives of the function f(x) = cos(3x2) that follow
are incorrect. What misconception occurs in each case?
(a) Incorrect: f'(x) = sin(3x²).
(b) Incorrect: f'(x) = sin(3x²) (6x) (6).
9. In the proof that
1
dx
√1-x²
that sin(sin-¹ x) = x. It is also true that sin-¹ (sinx) = x
could we have started with that inequality instead? Why
|| = |
(x) + cos(x).
(sin ¹x) =
or why not?
10. Both of the following
and tan-1
I
we used the fact
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