The derivative of the function y = cot¬1(cscx) is: is: cSc X cot x y' csc x cot x y' csc²x+1 csc?x+1 the above the above secx tan x y' = sec2x+1 the above none of them

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The derivative of the function
y = cot¬1(cscx) is:
csc X cotx
y'
csc x cot x
y'
csc²x+1
csc?x+1
the above
the above
secxtan x
y' =
sec2x+1
the above
none of them
Transcribed Image Text:The derivative of the function y = cot¬1(cscx) is: csc X cotx y' csc x cot x y' csc²x+1 csc?x+1 the above the above secxtan x y' = sec2x+1 the above none of them
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