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The derivation of the secant segments theorem is shown below. Provide the reasons for e step. Given: Secants AC and outside of a circle. AE intersect BE and CD have been added to the figure. Show: (AB)(AC) = (AD)(AE) A B C E

The derivation of the secant segments theorem is shown below. Provide the reasons for e step. Given: Secants AC and outside of a circle. AE intersect BE and CD have been added to the figure. Show: (AB)(AC) = (AD)(AE) A B C E

Elementary Geometry for College Students
Elementary Geometry for College Students
6th Edition
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Daniel C. Alexander, Geralyn M. Koeberlein
Chapter6: Circles
Section6.3: Line And Segment Relationships In The Circle
Problem 41E
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The derivation of the secant segments theorem is shown below. Provide the reasons for each step. Given: Secants AC and AE intersect outside of a circle. BE and CD have been added to the figure. Show: (AB)(AC) = (AD)(AE) A. B D с E
Transcribed Image Text:The derivation of the secant segments theorem is shown below. Provide the reasons for each step. Given: Secants AC and AE intersect outside of a circle. BE and CD have been added to the figure. Show: (AB)(AC) = (AD)(AE) A. B D с E
LA LA LBCD BED ΔACD ~ ΔΑΕΒ AB AE AD AC (AB)(AC) = (AD)(AE) Reason 1 Reason 2 Reason 3 Reason 4 Reason 5
Transcribed Image Text:LA LA LBCD BED ΔACD ~ ΔΑΕΒ AB AE AD AC (AB)(AC) = (AD)(AE) Reason 1 Reason 2 Reason 3 Reason 4 Reason 5
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