The density of the rectangular plate [2,4] × [3, 5] in the x, y-plane is p = y/(3 + xy) in kilograms per meter cubed, where x, y are in meters. The value of cos(3M), where M is the mass of the plate, is 0.223 0.988 0.549 -0.173 -0.992 0.545 -0.863 0.128

Solve these prism and cylinder exercises. Where necessary, round the answers to 2 decimal places unless otherwise specified. Compute the base area of a right circular cone that is 15.8 centimeters high and has a volume of 1070 cubic centimeters.

Solve these prism and cylinder exercises. Where necessary, round the answers to 2 decimal places unless otherwise specified. A solid brass casting in the shape of a right circular cone has a base diameter of 4.36 inches and a height of 3.94 inches. Find the weight of the casting. Brass weighs 0.302 pound per cubic inch.

Solve these prism and cylinder exercises. Where necessary, round the answers to 2 decimal places unless otherwise specified. Find the volume of a right circular cylinder that has a height of 4,600 inches and a base area of 53.00 square inches.

Solve these prism and cylinder exercises. Where necessary, round the answers to 2 decimal places unless otherwise specified. Compute the volume of a prism with a base area of 220.0 square centimeters and a height of 7.600 centimeters.

A soda can is made from 40 square inches of aluminum. Let x denote the radius of the top of the can, and let h denote the height, both in inches. a. Express the total surface area S of the can, using x and h. Note: The total surface area is the area of the top plus the area of the bottom plus the area of the cylinder. b. Using the fact that the total area is 40 square inches, express h in terms of x. c. Express the volume V of the can in terms of x.

Solve these prism and cylinder exercises. Where necessary, round the answers to 2 decimal places unless otherwise specified. Compute the height of a prism with a base area of 2.7 square feet and a volume of 4.86 cubic feet.

the weight W of a steel ball bearing varies directly with the cube of the bearing's radius r according to the formula W= 4/3 pi(p)(r)^3, where p is the density of the steel.  The surface area of a bearing varies directly as the square of its radius because A =  4 pi(r^2) a. Express the weight W of a bearing in terms of its surface area b. Express the bearing's surface area A in terms of its weight. c. For steel, p = 7.85 g/cm^3. What s the surface area of a bearing weighing 0.62 g?

The braking distance d, in meters, of a vehicle traveling at a velocity v, in meters per second, is given by the formula d = 2ug* is the coefficient of friction and g is the acceleration due to gravity. On Earth, where gx9.8 m/s. Complete parts (a) and (b) below. (a) Determine the braking distance of a car traveling at 55 km/hr on dry pavement (u = 0.80). (Be sure to convert the speed to meters per second.) The braking distance is about meters. (Simplify your answer. Round to the nearest integer as needed.) (b) Determine the braking distance of a car traveling at 63 mi/hr on wet pavement (u = 0.45). Give the final answer in feet. The braking distance is about feet. (Round to the nearest ten as needed.)

he density of Venus is similar to that of Earth. The mass of Venus is and its diameter is 12,100 km. Find the density of Venus in g/cm. The volume of sphere is given by ar'. A star is estimated to have a mass of 2 x 103% kg. Assuming it to be a sphere of average radius 7.0 x 10° km, calculate the average density of the star in units of grams per cubic centimeter. A rectangular solid measures 1.0 m by 5.6 cm by 2.1 dm. Express its volume in cubic meters and liters. Consider the addition of 15.4 to 28. What would a mathematician say the answer is? What would a scientist say? Justify the scientist's answer, not merely citing the rule, out explaining it. kg. anaidan ..ltinl.inn 16 b. 16 42 I/Lat uld - mathamntininn