The density of a puresubstance is its mass per unitvolume. The density of hexanehas been measured to be655.. Calculate the mass ofL455. mL of hexane.The density of a pure substance is its mass per unit volume. The density ofhexane has been measured to be 655hexane.Calculate the mass of 455. mL of

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Answered: The density of a pure substance is its…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The chemist measures the volume of the unknown liquid as 0.615 L and the mass of the unknown liquid as 385. g. Calculate the density of the liquid. Be sure your answer has the correct number of significant digits. Is it possible to identify the liquid? If it is possible to identify the liquid, do so.
2. An object has a volume of 0.0012 m3 and a mass of of 2.26 kg. Calculate the density of the object in g/cm3.
The mass of a certain atom is 2.086 x 10°22 g. This is the same mass as 2.086 x 10-16 mg. 2.086 x 10-25 kg. 2.086 x 10-28 Hg. O 2.086 x 10-31 ng.
a. Using the correct rules for multiplication/division and significant figures provide the answer for the following calculation. 6.98 x 89.44 = b. Using the correct rules for multiplication/division and significant figures provide the answer for the following calculation. 7831 x 76.987 = c. Using the correct rules for addition/subtraction and significant figures provide the answer for the following calculation. 7831 + 76.987 = d. Using the correct rules for addition/subtraction and significant figures provide the answer for the following calculation. 7831.67 + 76.987 = e. Using the correct rules for addition/subtraction and significant figures provide the answer for the following calculation. 7831.67 + 76.987 =
1. Why are units so important in measurement? Giving examples of measurements with no units should help. 2. What does it mean to say that 2 expressions are equivalent?
Q1. from 0.8778 g/mL, please calculate the mass (in ug) of 71.38 nL of liquid 1. following this information below The volume of a given liquid is defined as the amount of the space occupied by the liquid that fully spreads to fill the storage place in which it is kept. The mass present per unit volume is known as density. Given data: Mass of empty pycnometer is 51.870 g. Mass of pycnometer when filled with liquid 1 is 86.313 g. Volume of pycnometer is 39.24 mL. Calculations The mass of liquid 1 can be calculated as shown below: Mass of liquid 1===(Mass of pycnometer when filled with liquid 1)−(Mass of empty pycnometer)86.313−51.87034.443 gMass of liquid 1=Mass of pycnometer when filled with liquid 1-Mass of empty pycnometer=86.313-51.870=34.443 g Volume of liquid 1 = Volume of pycnometer Hence the volume of liquid 1 is 39.24 mL Now, the density of liquid 1 can be calculated as follows: Density of liquid 1===Mass of liquid 1Volume of liquid 134.443 g39.24 mL0.8778…
My dog is 1 m heigh. A meter is a unit of mass. A meter is a unit of volume. A meter is a unit of length. A meter is a unit of temperature.
A. Type the number 1340000 in scientific notation. B. Type the number 0.000354 in scientific notation. C. Type the number 3.14×103 in standard notation.
3. A story calls for the hero sprinting off with a gold brick and the author wants to determine if that is feasible. If the gold brick is the same size as a typical brick, 1020 cm³, then calculate the mass of gold in pounds. Based upon your result, do you think that the author should include this in the plot? The density of gold is 19.3 g/cm³. MP b of side ic ent to Jeg of p DIS eril I I-0- 3 1 T CA

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