The demand for a new computer game can be modeled by p(x) = 53.5-81nx, where p(x) is the price consumers will pay, in dollars and x is the number of games sold, in thousands. Recall that total revenue is given by R(x)=x- p(x) a) Find the marginal revenue, R'(x). b) How many games will be sold if the price is $40?
The demand for a new computer game can be modeled by p(x) = 53.5-81nx, where p(x) is the price consumers will pay, in dollars and x is the number of games sold, in thousands. Recall that total revenue is given by R(x)=x- p(x) a) Find the marginal revenue, R'(x). b) How many games will be sold if the price is $40?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Mathematical Modeling of Game Demand and Revenue**
The demand for a new computer game can be modeled by the equation \( p(x) = 53.5 - 8 \ln x \), where \( p(x) \) represents the price consumers are willing to pay, measured in dollars, and \( x \) represents the quantity of games sold, measured in thousands.
The total revenue \( R(x) \) is calculated by the formula:
\[ R(x) = x \cdot p(x) \]
### Tasks:
a) **Find the Marginal Revenue, \( R'(x) \).**
b) **Determine the Number of Games Sold if the Price is $40.**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F939f19e0-6626-477a-ba7a-4282434e880a%2Fd8e1e4e8-64f4-45dc-901d-03287f7f8350%2F3zc5if3_processed.png&w=3840&q=75)
Transcribed Image Text:**Mathematical Modeling of Game Demand and Revenue**
The demand for a new computer game can be modeled by the equation \( p(x) = 53.5 - 8 \ln x \), where \( p(x) \) represents the price consumers are willing to pay, measured in dollars, and \( x \) represents the quantity of games sold, measured in thousands.
The total revenue \( R(x) \) is calculated by the formula:
\[ R(x) = x \cdot p(x) \]
### Tasks:
a) **Find the Marginal Revenue, \( R'(x) \).**
b) **Determine the Number of Games Sold if the Price is $40.**
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