The Delaware tourism board selected a simple random sample of 50 full-service restaurants located within the state. Considering all possible such samples with n = 50, what is the probability of selecting one whose mean is greater than 103.4? That is, p(M > 103.4) =
The Delaware tourism board selected a simple random sample of 50 full-service restaurants located within the state. Considering all possible such samples with n = 50, what is the probability of selecting one whose mean is greater than 103.4? That is, p(M > 103.4) =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Please help with my stats hw
![6. Three different distributions
There are 559 full-service restaurants in Delaware. The mean number of seats per restaurant is 99.2. [Source: Data based on the 2002 Economic
Census from the US Census Bureau.]
Suppose that the true population mean u = 99.2 and standard deviation o = 20.5 are unknown to the Delaware tourism board. They select a simple
random sample of 50 full-service restaurants located within the state to estimate u. The mean number of seats per restaurant in the sample is M =
103.4, with a sample standard deviation of s = 18.2.
The standard deviation of the distribution of sample means (that is, the standard error, OM) is
(Note: Although p and o are unknown to
the Delaware tourism board, they are known to you for the purposes of calculating these answers.)
The standard or typical average difference between the mean number of seats in the 559 full-service restaurants in Delaware (p = 99.2) and one
randomly selected full-service restaurant in Delaware is
The standard or typical average difference between the mean number of seats in the sample of 50 restaurants (M = 103.4) and one randomly
selected restaurant in that sample is
The standard or typical average difference between the mean number of seats in the 559 full-service restaurants in Delaware (u = 99.2) and the
sample mean of any sample of size 50 is
The z-score that locates the mean number of seats in the Delaware tourism board's sample (M = 103.4) in the distribution of sample means is
Use the unit normal tables and accompanying figures to answer the question that follows. To use the tables, select the desired range of z-score values.
A table of the proportions of the normal distribution corresponding to that range of z-scores will appear.
Suggestion: Make a sketch of the area under the normal distribution you are seeking. This sketch will help you determine which column(s) of the
normal table to use in determining the appropriate probability.
D: Between 0
and z
Body B
Tail C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8a28a380-2121-4133-b35d-e9a8f94c0516%2F8d66e1dd-7d42-4f37-9e91-6649baa9cd59%2F2ar13sb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. Three different distributions
There are 559 full-service restaurants in Delaware. The mean number of seats per restaurant is 99.2. [Source: Data based on the 2002 Economic
Census from the US Census Bureau.]
Suppose that the true population mean u = 99.2 and standard deviation o = 20.5 are unknown to the Delaware tourism board. They select a simple
random sample of 50 full-service restaurants located within the state to estimate u. The mean number of seats per restaurant in the sample is M =
103.4, with a sample standard deviation of s = 18.2.
The standard deviation of the distribution of sample means (that is, the standard error, OM) is
(Note: Although p and o are unknown to
the Delaware tourism board, they are known to you for the purposes of calculating these answers.)
The standard or typical average difference between the mean number of seats in the 559 full-service restaurants in Delaware (p = 99.2) and one
randomly selected full-service restaurant in Delaware is
The standard or typical average difference between the mean number of seats in the sample of 50 restaurants (M = 103.4) and one randomly
selected restaurant in that sample is
The standard or typical average difference between the mean number of seats in the 559 full-service restaurants in Delaware (u = 99.2) and the
sample mean of any sample of size 50 is
The z-score that locates the mean number of seats in the Delaware tourism board's sample (M = 103.4) in the distribution of sample means is
Use the unit normal tables and accompanying figures to answer the question that follows. To use the tables, select the desired range of z-score values.
A table of the proportions of the normal distribution corresponding to that range of z-scores will appear.
Suggestion: Make a sketch of the area under the normal distribution you are seeking. This sketch will help you determine which column(s) of the
normal table to use in determining the appropriate probability.
D: Between 0
and z
Body B
Tail C
Transcribed Image Text:1.00 szs 1.24:
1.25 szs 1.49:
1.50 szs 1.74:
1.75 szs 1.99
0.00 szs 0.24:
0.50 szs 0.74:
0.75 szs0.99:
0.25 szs0.49:
2.75 szs 2.99:
3.00 szs 3.24:
3.30 szS 4.00:
2.00 szs 2.24:
2.25 szs 2.49:
2.50 szs 2.74:
B: Proportion in Body
C: Proportion in Tail
D: Proportion Between Mean and z
.5000
.0000
.00
.5000
.01
.5040
.4960
.0040
.02
.5080
.4920
.0080
.03
.5120
.4880
.0120
.04
.5160
.4840
.0160
.05
.5199
.4801
.0199
.06
.5239
.4761
.0239
.07
.5279
.4721
.0279
.08
.5319
.4681
.0319
.09
.5359
.4641
.0359
.10
.5398
.4602
.0398
.11
.5438
.4562
.0438
.12
.5478
.4522
.0478
.13
.5517
.4483
.0517
.14
.5557
.4443
.0557
.15
.5596
.4404
.0596
.16
.5636
.4364
.0636
.17
.5675
4325
.0675
.18
.5714
.4286
.0714
.19
.5753
.4247
.0753
20
.5793
.4207
.0793
.21
.5832
.4168
.0832
.22
.5871
.4129
.0871
23
.5910
.4090
.0910
.24
.5948
.4052
.0948
The Delaware tourism board selected a simple random sample of 50 full-service restaurants located within the state. Considering all possible such
samples with n = 50, what is the probability of selecting one whose mean is greater than 103.4? That is, p(M > 103.4) =
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
Recommended textbooks for you
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman