The dehydration butanol of alumina is carried out over a silica alumina cata- lyst at 680 K. CH CH CH CH 0H~CH CH = CHCH3 + HzO The rate law is with k = 0.065 mollgcat•h•atm and Ksu = 0.42 atm- 1 • Pure butanol enters a thin tubed packed-bed reactor at a molar flow rate 50 kmol/hr and a pressure of 10 atm (l013•kPa). (a) What PBR catalyst weight is necessary to achieve 80% conversion in the absence of pressure drop? Plot and analyze X, y, f (i.e., (v/v0)) and reac- tion rate, -r~, as a function of catalyst weight
The dehydration butanol of alumina is carried out over a silica alumina cata- lyst at 680 K. CH CH CH CH 0H~CH CH = CHCH3 + HzO The rate law is with k = 0.065 mollgcat•h•atm and Ksu = 0.42 atm- 1 • Pure butanol enters a thin tubed packed-bed reactor at a molar flow rate 50 kmol/hr and a pressure of 10 atm (l013•kPa). (a) What PBR catalyst weight is necessary to achieve 80% conversion in the absence of pressure drop? Plot and analyze X, y, f (i.e., (v/v0)) and reac- tion rate, -r~, as a function of catalyst weight
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Question
100%
The dehydration butanol of alumina is carried out over a silica alumina cata-
lyst at 680 K.
CH CH CH CH 0H~CH CH = CHCH3 + HzO
The rate law is
with k = 0.065 mollgcat•h•atm and Ksu = 0.42 atm- 1
• Pure butanol enters a
thin tubed packed-bed reactor at a molar flow rate 50 kmol/hr and a pressure
of 10 atm (l013•kPa).
(a) What PBR catalyst weight is necessary to achieve 80% conversion in the
absence of pressure drop? Plot and analyze X, y, f (i.e., (v/v0)) and reac-
tion rate, -r~, as a function of catalyst weight
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