The deflection of a uniform beam subject to a linearly increasing distributed load can be computed as My 120ELL (- +21²³-L²x) given that L-600 cm, E-50,000 kN/cm2, /-30,000 cm4, and wo-2.5 kN/cm. Use the golden-section search to determine the point of maximum deflection with the initial guesses of x= 0 and x-L. (Round final answers to four decimal places.) cm. cm where the function has a value of y=[ The result is converging on the true minimum at x=
The deflection of a uniform beam subject to a linearly increasing distributed load can be computed as My 120ELL (- +21²³-L²x) given that L-600 cm, E-50,000 kN/cm2, /-30,000 cm4, and wo-2.5 kN/cm. Use the golden-section search to determine the point of maximum deflection with the initial guesses of x= 0 and x-L. (Round final answers to four decimal places.) cm. cm where the function has a value of y=[ The result is converging on the true minimum at x=
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
![The deflection of a uniform beam subject to a linearly increasing distributed load can be computed as
My
YTELL
+21²-L¹z)
given that L-600 cm, E=50,000 kN/cm2, /-30,000 cm4, and wo-2.5 kN/cm.
Use the golden-section search to determine the point of maximum deflection with the initial guesses of x=0 and x=L. (Round the
final answers to four decimal places.)
cm.
cm where the function has a value of y=1
The result is converging on the true minimum at x=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2a873538-8e26-4d67-87a4-f8d21d3d9aed%2Fdd707c60-74c9-4489-8cae-07599eadb07f%2Fe375h3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The deflection of a uniform beam subject to a linearly increasing distributed load can be computed as
My
YTELL
+21²-L¹z)
given that L-600 cm, E=50,000 kN/cm2, /-30,000 cm4, and wo-2.5 kN/cm.
Use the golden-section search to determine the point of maximum deflection with the initial guesses of x=0 and x=L. (Round the
final answers to four decimal places.)
cm.
cm where the function has a value of y=1
The result is converging on the true minimum at x=
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