The deflection angles of two intermediate points A and B of a highway curve are given below. The chord distance between points A and B is CAB while the long chord is C. Compute the elements of the curve and find the stationing end of the simple curve. **No space before and after the plus sign for stationing. Station A B CAB с Sta of P.I. Deflection Angles 5° 16' 12° 17' Chord distance (m) 20 120 90+400 Elements of the given circular curve Radius (m) Intersection Angle (degree-decimal) Tangent Distance Length of Curve (m) Degree of Curve (degree-decimal) Sta of P.C. Sta of P.T.

The deflection angles of two intermediate points A and B of a highway curve are given below. The chord distance between points A and B is CAB while the long chord is C. Compute the elements of the curve and find the stationing end of the simple curve. **No space before and after the plus sign for stationing. Station A B CAB с Sta of P.I. Deflection Angles 5° 16' 12° 17' Chord distance (m) 20 120 90+400 Elements of the given circular curve Radius (m) Intersection Angle (degree-decimal) Tangent Distance Length of Curve (m) Degree of Curve (degree-decimal) Sta of P.C. Sta of P.T.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The distance between two intermediate points A and B on a simple curve is 60 m. Their deflection angles are respectively 4° and 10° measured from tangent through PC. 1. Compute the radius of the simple curve. 2. Compute the arc length from PC to A. 3. Compute the chord length from PC to B.
provide solution, illustration and sketches
The azimuth of the tangents of the simple curve is 490 degrees and 764 degrees respectively. The radius of the curve is 211.2 meters. Station A is lying on the curve having a deflection angle of 9 degrees from PT. Determine the length of chord from PC to PT in meters.
A horizontal curve with a deflection angle of 60o30' and degree of curvature of 5o as shown in Figure 5 is to be set out at whole station intervals of 100ft. If the point of curvature (PC) is located at a station 121+25.66, determine.i. the length of the curve and the station of PTii. the deflection angles VAp, VAq, VAv and Vas
Problem 4. Derive the expression for the offset y of any point of the curve above the beginning of a vertical curve that results in the following equation:
H.M 6: Use the following figure, to calculate the curve elevation of full and main stations by using Analytic method? P.V.I -3% P.Y.T P.V.C 36. Som 41 +60 =240m 十
the deflection angles of two intermediate points x and y on a simple curve measured from the tangent passing through pc are 6.97° and 12.8°, respectively. the distance along the curve between x and y is 34.72 m. compute the for the degree of curve in degrees. use arc basis.
The azimuth of the tangents of the simple curve is 480° and 740° respectively. The radius of the curve is 180m. Station A is lying on the curve having a deflection angle of 8° from PT. Determine the length of curve from PT to Point A in meters.
Answer letter c.
Two tangents intersect at station 26+050. A compound curve laid their tangents has the following data: 1=31° 12=36° D1=3° D2=5° a. Compute the stationing of the P.C. b. Compute the stationing of the P.T. If the P.T. is moved 15m. out from the center, compute the stationing of the new P.T. with the P.C.C. remaining unchanged. C.
Q4) Circular curve connects two straights intersected at a station (20+20.10). If the deflection angle(40°), and coordinates of PC and PT are(100,200)m and(280,120)m respectively. Calculate:- 1- All the elements of the horizontal curve - 2- Setting out curve by P.I method. M عقيل يما دعما مرد مسمى
Additional question:1. The value of intersection Angle of the Second curve is 23.66 deg (103.7553 - 84.0945). What is the length of curve 2? 2. What is the value of the intersection angle of the first curve? 3. What is the curve length of the first curve?