Consider the region S shown in the figure below and take note of the following points of intersection: Curve 1 Curve Point of Intersection 2 y = −(x+3)² + 9x-axis (-6,0) y = −(x+3)² +9y=x² (-3,9) y = x² y-axis origin y = (x+3)² +9 =x ∞0 I LO 5 Y

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Chapter1: Functions And Models
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Consider the region S shown in the figure
below and take note of the following
points of intersection:
Curve 1
Curve Point of
Intersection
2
y =
−(x+3)² + 9x-axis (-6,0)
y = −(x+3)² +9y=x² (-3,9)
y = x²
y-axis origin
y = (x+3)² +9
S
تن.....
Q
= x
∞0
I
5
Y
8
Transcribed Image Text:Consider the region S shown in the figure below and take note of the following points of intersection: Curve 1 Curve Point of Intersection 2 y = −(x+3)² + 9x-axis (-6,0) y = −(x+3)² +9y=x² (-3,9) y = x² y-axis origin y = (x+3)² +9 S تن..... Q = x ∞0 I 5 Y 8
The definite integral that will give the area
of the region S using HORIZONTAL strips
is
+9
Solve -
9-y dy
0
+9
O
°\√-3-√3) dy
-3
°
[
[−-(x + 3)² +9] dx +
1₁
[²₂ 20²
-6
-3
0
₁ [(x + 3)² +9− x²] da
dx
-6
O All of the above
None of the above
x² dx
Transcribed Image Text:The definite integral that will give the area of the region S using HORIZONTAL strips is +9 Solve - 9-y dy 0 +9 O °\√-3-√3) dy -3 ° [ [−-(x + 3)² +9] dx + 1₁ [²₂ 20² -6 -3 0 ₁ [(x + 3)² +9− x²] da dx -6 O All of the above None of the above x² dx
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