The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test.x 0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972 Dy 0.7963 0.84770.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472b. Let c, be the number of MAD values in the first sample that are greater than the largest MAD value in the second sample. Also, let c, be the number of MAD values in the second sample that are greater thanthe largest MAD value in the first sample.c. If the sample sizes are equal, use a critical value of 5. If not, use the formula below to find the critical value.log (a/2)n,logn, +n2The critical value is.(Type an integer or decimal rounded to one decimal place as needed.)The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test.x 0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972Oy 0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472logn, +n2The critical value is.(Type an integer or decimal rounded to one decimal place as needed.)d. If c, is greater than or equal to the critical value, then conclude that o >o. If c, is greater than or equal to the critical value, then conclude that o >o?. Otherwise, fail to reject the null hypothesis thato: =0. Which conclusion can be drawn? Choose the correct answer below.OA. rejecto? = a3 • infav or ofa? >o}O B. failtorejecto? =o}OC. rejecta? = o? • infav or ofa >a? The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test.|x 0.7923 0.7889 0.8173 0.7817 0.7915|0.8031 0.7837 0.7975|0.7871 0.7972 -y 0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472a. For the first sample, find the mean absolute deviation (MAD) of each value. Do the same for the second sample.Find the MAD of each x value. Recall that the MAD of the sample value is x-x.0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972MAD O O ODO(Round to four decimal places as needed.)Find the MAD of each y value.0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472MAD OO OOOO OOOO(Round to four decimal places as needed.)b. Let c, be the number of MAD values in the first sample that are greater than the largest MAD value in the second sample. Also, let c, be the number of MAD values in the second sample that are greater thanthe largest MAD value in the first sample.

Mean absolute deviation, otherwise called MAD is a measure of descriptive statistics.

Answered: The data shows the weights of samples…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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