The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test. x 0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972 y 0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test.
x 0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972 D
y 0.7963 0.84770.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472
b. Let c, be the number of MAD values in the first sample that are greater than the largest MAD value in the second sample. Also, let c, be the number of MAD values in the second sample that are greater than
the largest MAD value in the first sample.
c. If the sample sizes are equal, use a critical value of 5. If not, use the formula below to find the critical value.
log (a/2)
n,
log
n, +n2
The critical value is.
(Type an integer or decimal rounded to one decimal place as needed.)
The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test.
x 0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972O
y 0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472
log
n, +n2
The critical value is.
(Type an integer or decimal rounded to one decimal place as needed.)
d. If c, is greater than or equal to the critical value, then conclude that o >o. If c, is greater than or equal to the critical value, then conclude that o >o?. Otherwise, fail to reject the null hypothesis that
o: =0. Which conclusion can be drawn? Choose the correct answer below.
OA. rejecto? = a3 • infav or ofa? >o}
O B. failtorejecto? =o}
OC. rejecta? = o? • infav or ofa >a?
Transcribed Image Text:The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test. x 0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972 D y 0.7963 0.84770.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472 b. Let c, be the number of MAD values in the first sample that are greater than the largest MAD value in the second sample. Also, let c, be the number of MAD values in the second sample that are greater than the largest MAD value in the first sample. c. If the sample sizes are equal, use a critical value of 5. If not, use the formula below to find the critical value. log (a/2) n, log n, +n2 The critical value is. (Type an integer or decimal rounded to one decimal place as needed.) The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test. x 0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972O y 0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472 log n, +n2 The critical value is. (Type an integer or decimal rounded to one decimal place as needed.) d. If c, is greater than or equal to the critical value, then conclude that o >o. If c, is greater than or equal to the critical value, then conclude that o >o?. Otherwise, fail to reject the null hypothesis that o: =0. Which conclusion can be drawn? Choose the correct answer below. OA. rejecto? = a3 • infav or ofa? >o} O B. failtorejecto? =o} OC. rejecta? = o? • infav or ofa >a?
The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test.
|x 0.7923 0.7889 0.8173 0.7817 0.7915|0.8031 0.7837 0.7975|0.7871 0.7972 -
y 0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472
a. For the first sample, find the mean absolute deviation (MAD) of each value. Do the same for the second sample.
Find the MAD of each x value. Recall that the MAD of the sample value is x-x.
0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972
MAD O O ODO
(Round to four decimal places as needed.)
Find the MAD of each y value.
0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472
MAD OO OOOO OOOO
(Round to four decimal places as needed.)
b. Let c, be the number of MAD values in the first sample that are greater than the largest MAD value in the second sample. Also, let c, be the number of MAD values in the second sample that are greater than
the largest MAD value in the first sample.
Transcribed Image Text:The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test. |x 0.7923 0.7889 0.8173 0.7817 0.7915|0.8031 0.7837 0.7975|0.7871 0.7972 - y 0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472 a. For the first sample, find the mean absolute deviation (MAD) of each value. Do the same for the second sample. Find the MAD of each x value. Recall that the MAD of the sample value is x-x. 0.7923 0.7889 0.8173 0.7817 0.7915 0.8031 0.7837 0.7975 0.7871 0.7972 MAD O O ODO (Round to four decimal places as needed.) Find the MAD of each y value. 0.7963 0.8477 0.8014 0.8406 0.8296 0.8268 0.7877 0.8094 0.8082 0.8472 MAD OO OOOO OOOO (Round to four decimal places as needed.) b. Let c, be the number of MAD values in the first sample that are greater than the largest MAD value in the second sample. Also, let c, be the number of MAD values in the second sample that are greater than the largest MAD value in the first sample.
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