The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test. x0,7819 0.8048 0.81640.7841 0.8048 0.7831 0.8019 0.78530.7857 0.80930 y0.7955 0.8012 0.8094 0.7952 0.7985 0.7953 0.7893 0.8227 0.84780.7995 a. For the first sample, find the mean absolute deviation (MAD) of each value. Do the same for the second sample. Find the MAD of each x value. Recall that the MAD of the sample value is Ix-x|. 0.7819 0.8048 0.8164 0.7841 0.8048 0.7831 0.8019 0.7853 0.7857 0.8093 MAD O O O (Round to four decimal places as needed.) O O O O O O Find the MAD of each y value. y 0.7955 0.8012 0.8094 0.7952 0.7985 0.7953 0.7893 0.8227 0.8478 0.7995 MAD OO O (Round to four decimal places as needed.) O O O O O O b. Let c, be the number of MAD values in the first sample that are greater than the largest MAD value in the second sample. Also, let c, be the number of MAD values in the second sample that are greater than the largest MAD value in the first sample. c. If the sample sizes are equal, use a critical value of 5. If not, use the formula below to find the critical value. log (a /2) log n + n2 The critical value is (Type an integer or decimal rounded to one decimal place as needed.)
The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count five" test. x0,7819 0.8048 0.81640.7841 0.8048 0.7831 0.8019 0.78530.7857 0.80930 y0.7955 0.8012 0.8094 0.7952 0.7985 0.7953 0.7893 0.8227 0.84780.7995 a. For the first sample, find the mean absolute deviation (MAD) of each value. Do the same for the second sample. Find the MAD of each x value. Recall that the MAD of the sample value is Ix-x|. 0.7819 0.8048 0.8164 0.7841 0.8048 0.7831 0.8019 0.7853 0.7857 0.8093 MAD O O O (Round to four decimal places as needed.) O O O O O O Find the MAD of each y value. y 0.7955 0.8012 0.8094 0.7952 0.7985 0.7953 0.7893 0.8227 0.8478 0.7995 MAD OO O (Round to four decimal places as needed.) O O O O O O b. Let c, be the number of MAD values in the first sample that are greater than the largest MAD value in the second sample. Also, let c, be the number of MAD values in the second sample that are greater than the largest MAD value in the first sample. c. If the sample sizes are equal, use a critical value of 5. If not, use the formula below to find the critical value. log (a /2) log n + n2 The critical value is (Type an integer or decimal rounded to one decimal place as needed.)
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
Section: Chapter Questions
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Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
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Transcribed Image Text:The data shows the weights of samples of two different sodas. Test the claim that the weights of the two sodas have the same standard deviation using a "count
five" test.
x0.7819 0.8048 0.8164 0.7841 0.8048 0.7831 0.8019 0.7853 0.7857|0.8093
y0.7955 0.80120.8094 0.7952 0.7985 0.7953 0.7893 0.8227 0.8478 0.7995
a. For the first sample, find the mean absolute deviation (MAD) of each value. Do the same for the second sample.
Find the MAD of each x value. Recall that the MAD of the sample value is |x - x.
0.7819 0.8048 0.8164 0.7841 0.8048 0,7831 0.8019 0,7853 0,7857 0,8093
MAD O O O O
(Round to four decimal places as needed.)
Find the MAD of each y value.
y
0.7955 0,8012 0.8094 0.7952 0.7985 0,7953 0,7893 0.8227 0.8478 0,7995
O O
MAD
(Round to four decimal places as needed.)
b. Let c, be the number of MAD values in the first sample that are greater than the largest MAD value in the second sample. Also, let cz be the number of MAD
values in the second sample that are greater than the largest MAD value in the first sample.
C1
C2
c. If the sample sizes are egual, use a critical value of 5. If not, use the formula below to find the critical value.
Ιog (α/2)
log
n, + n2
The critical value is
(Type an integer or decimal rounded to one decimal place as needed.)
d. If c, is greater than or equal to the critical value, then conclude that of >o3. If cz is greater than or equal to the critical value, then conclude that o3 >o3.
Otherwise, fail to reject the null hypothesis that o =o5. Which conclusion can be drawn? Choose the correct answer below.
O A. fail to reject o =o2
O B. reject o? =o3 in favor of o? >o3
OC. reject o? =o in favor of o >o
Click to select your answer(s).
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