The data show the chest se and wigf severbean Fed e ngrsion eqution ting chest se be he ndepandent varatle Then nd he best preded weighe of a bewia chest se of S7 ndes l the reut doset he actual weight of 356 pound? Usesignificance level of6 05 Chest sienches Weightpounda Cick the icon vie the ortical values of the Pearson comlation coeicientr What is the regression qtion .Roundone decimal plac ded)
The data show the chest se and wigf severbean Fed e ngrsion eqution ting chest se be he ndepandent varatle Then nd he best preded weighe of a bewia chest se of S7 ndes l the reut doset he actual weight of 356 pound? Usesignificance level of6 05 Chest sienches Weightpounda Cick the icon vie the ortical values of the Pearson comlation coeicientr What is the regression qtion .Roundone decimal plac ded)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
1)
Check Images
2) What is the best predicted weight of a bear with a chest size of 57 inches?
3) The best predicted weight for a bear with a chest size of 57 inches is ? pounds.
(Round to one decimal place as needed.)
Is the result close to the actual weight of 356 pounds?
Transcribed Image Text:The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 57 inches. Is the result
close to the actual weight of 356 pounds? Use a significance level of 0 05.
Chest sie (inches)
Weight (pounds)
T5 4 51 58 44
60 o
425 266 347 453 282 400
Click the icon to view the critical values of the Pearson correlation coefficient
What is the regression equation?
y-D•D (Round to one decimal place as needed)
Transcribed Image Text:Critical Values of the Pearson Correlation Coefficient r
NOTE: To test H, p =D0
Jagainst H, p#0, reject H,
f the absolute value of r is
greater than the critical
value in the table.
a = 0.05
a = 0.01
0.950
0.878
0.990
0.959
0.917
0.875
0.834
4
6
0.811
0.754
0.707
0.666
0.632
0.602
0.576
0.553
0.798
0.765
0.735
0.708
9
10
11
12
13
0.684
0.661
0.641
0.623
0.606
14
0.532
0.514
0.497
0.482
0.468
0.456
0.444
0.396
15
16
17
18
0.590
0.575
0.561
0.505
19
20
25
0.361
0.335
0.312
0.294
0.279
30
35
0.463
0.430
0.402
0.378
0.361
0.330
0.305
0.286
40
45
50
60
70
0.254
0.236
80
0.220
0.269
0.256
a= 0.01
90
0.207
100
0.196
a= 0.05
Expert Solution
Step 1
Create a table with column labels .
| 58 | 425 | 24650 | 3364 | 180625 |
| 48 | 266 | 12768 | 2304 | 70756 |
| 51 | 347 | 17697 | 2601 | 120409 |
| 58 | 453 | 26274 | 3364 | 205209 |
| 44 | 262 | 11528 | 1936 | 68644 |
| 60 | 406 | 24360 | 3600 | 164836 |
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