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The data should fit a linear model of the form log k EA/(2.303RT), where A is the preexponential log A factor, and Ris the gas constant. (a) Fit the data to a straight line of the form log k = a 1000b/ T. - *(b) Find the slope, intercept, and standard error of the estimate. *(c) Noting that E, = -b× 2.303R X 1000, find the activation energy and its standard deviation (Use R= 1.987 cal mol K-'). *(d) A theoretical prediction gave EA = 41.00 kcal mol'K. Test the null hypothesis that EA is this value at the 95% confidence level.

The data should fit a linear model of the form log k EA/(2.303RT), where A is the preexponential log A factor, and Ris the gas constant. (a) Fit the data to a straight line of the form log k = a 1000b/ T. - *(b) Find the slope, intercept, and standard error of the estimate. *(c) Noting that E, = -b× 2.303R X 1000, find the activation energy and its standard deviation (Use R= 1.987 cal mol K-'). *(d) A theoretical prediction gave EA = 41.00 kcal mol'K. Test the null hypothesis that EA is this value at the 95% confidence level.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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8-19. A study was made to determine the activation energy E, for a chemical reaction. The rate constant k was de- termined as a function of temperature T, and the data in the table below obtained. Т, К k, s-1 599 0.00054 629 0.0025 647 0.0052 666 0.014 683 0.025 700 0.064 The data should fit a linear model of the form log k log A – EA/(2.303RT), where A is the preexponential factor, and R is the gas constant. (a) Fit the data to a straight line of the form log k = a - 1000b/ T. *(b) Find the slope, intercept, and standard error of the estimate. *(c) Noting that E, the activation energy and its standard deviation (Use R = 1.987 cal mol K-'). *(d) A theoretical prediction gave EA molK. Test the null hypothesis that EA is this -6 X 2.303R X 1000, find = 41.00 kcal value at the 95% confidence level.
Transcribed Image Text:8-19. A study was made to determine the activation energy E, for a chemical reaction. The rate constant k was de- termined as a function of temperature T, and the data in the table below obtained. Т, К k, s-1 599 0.00054 629 0.0025 647 0.0052 666 0.014 683 0.025 700 0.064 The data should fit a linear model of the form log k log A – EA/(2.303RT), where A is the preexponential factor, and R is the gas constant. (a) Fit the data to a straight line of the form log k = a - 1000b/ T. *(b) Find the slope, intercept, and standard error of the estimate. *(c) Noting that E, the activation energy and its standard deviation (Use R = 1.987 cal mol K-'). *(d) A theoretical prediction gave EA molK. Test the null hypothesis that EA is this -6 X 2.303R X 1000, find = 41.00 kcal value at the 95% confidence level.
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