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The currents in the circuit shown can be determined from the solutions of the given system of equations, which were obtained by applying irchoff's laws 20 V 352 8 V 402 502 202 12 V www 30 V 2.502 202 www 1.52 www 352 14 V 1.5 -5i₂-2i4 +8.5i, -1.5i, = -30 - 2i3 -1.5i, +8i = 0 Solve the system of linear equations using the Gauss-Seidel method 8i, 4i₂ i 20 = -4i, +11.5i, -2.5i, -5i, = -12 -2.5i₂ +4.5i, -2i = 14 -i, +3i₁-2i=8

The currents in the circuit shown can be determined from the solutions of the given system of equations, which were obtained by applying irchoff's laws 20 V 352 8 V 402 502 202 12 V www 30 V 2.502 202 www 1.52 www 352 14 V 1.5 -5i₂-2i4 +8.5i, -1.5i, = -30 - 2i3 -1.5i, +8i = 0 Solve the system of linear equations using the Gauss-Seidel method 8i, 4i₂ i 20 = -4i, +11.5i, -2.5i, -5i, = -12 -2.5i₂ +4.5i, -2i = 14 -i, +3i₁-2i=8

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The currents in the circuit shown can be determined from the solutions of the given system of equations, which were obtained by applying irchoff's laws 20 V 8i, -41₂-14 = 20 −4i₁ +11.5i₂ -2.5i₂ - 5i, = -12 -2.5i₂ +4.5i₂-2i = 14 -i, +3i4 - 2i = 8 -5i₂-2i4 +8.5i-1.5i = -30 - 2i3 -1.5i, +8i = 0 Solve the system of linear equations using the Gauss-Seidel method 10 352 8 V 402 502 1202 30 V 12 V 2.502 252 w 1.502, 382 14 V 1.50
Transcribed Image Text:The currents in the circuit shown can be determined from the solutions of the given system of equations, which were obtained by applying irchoff's laws 20 V 8i, -41₂-14 = 20 −4i₁ +11.5i₂ -2.5i₂ - 5i, = -12 -2.5i₂ +4.5i₂-2i = 14 -i, +3i4 - 2i = 8 -5i₂-2i4 +8.5i-1.5i = -30 - 2i3 -1.5i, +8i = 0 Solve the system of linear equations using the Gauss-Seidel method 10 352 8 V 402 502 1202 30 V 12 V 2.502 252 w 1.502, 382 14 V 1.50
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