The current through a N = 175-turn coil with cross-sectional area, A = 0.0424 m², is decreasing at a steady rate. When the current drops from 5.43 A to 4.43 A over a period of 0.635 sec, the induced emf is 12.7 V. (a) What is the inductance of the coil? L = 0.0461 xH (b) Calculate the change in the energy density stored in the magnetic field of the coil. Aug = 4.637e-12 X MJ
The current through a N = 175-turn coil with cross-sectional area, A = 0.0424 m², is decreasing at a steady rate. When the current drops from 5.43 A to 4.43 A over a period of 0.635 sec, the induced emf is 12.7 V. (a) What is the inductance of the coil? L = 0.0461 xH (b) Calculate the change in the energy density stored in the magnetic field of the coil. Aug = 4.637e-12 X MJ
Related questions
Question
Transcribed Image Text:The current through a N = 175-turn coil with cross-sectional area, A = 0.0424 m², is decreasing at a steady rate.
When the current drops from 5.43 A to 4.43 A over a period of 0.635 sec, the induced emf is 12.7 V.
(a) What is the inductance of the coil?
L = 0.0461
(b) Calculate the change in the energy density stored in the magnetic field of the coil.
X MJ
Aug
XH
= 4.637e-12
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step 1: Know the concept:
VIEWStep 2: (a) Calculate the inductance:
VIEWStep 3: (b) Find the relation between the magnetic field and the current:
VIEWStep 4: (b) Find the expression for the change in the energy density stored in the magnetic field:
VIEWStep 5: (b) Calculate the change in the energy density stored in the magnetic field:
VIEWSolution
VIEW
Step by step
Solved in 6 steps
