The current through a N = 175-turn coil with cross-sectional area, A = 0.0424 m², is decreasing at a steady rate. When the current drops from 5.43 A to 4.43 A over a period of 0.635 sec, the induced emf is 12.7 V. (a) What is the inductance of the coil? L = 0.0461 xH (b) Calculate the change in the energy density stored in the magnetic field of the coil. Aug = 4.637e-12 X MJ
The current through a N = 175-turn coil with cross-sectional area, A = 0.0424 m², is decreasing at a steady rate. When the current drops from 5.43 A to 4.43 A over a period of 0.635 sec, the induced emf is 12.7 V. (a) What is the inductance of the coil? L = 0.0461 xH (b) Calculate the change in the energy density stored in the magnetic field of the coil. Aug = 4.637e-12 X MJ
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![The current through a N = 175-turn coil with cross-sectional area, A = 0.0424 m², is decreasing at a steady rate.
When the current drops from 5.43 A to 4.43 A over a period of 0.635 sec, the induced emf is 12.7 V.
(a) What is the inductance of the coil?
L = 0.0461
(b) Calculate the change in the energy density stored in the magnetic field of the coil.
X MJ
Aug
XH
= 4.637e-12](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5aeaefbb-8161-4211-bb0a-b05d203dda3a%2F4889db1f-70a4-44b0-8790-0d557f777f8a%2F66xsz9_processed.png&w=3840&q=75)
Transcribed Image Text:The current through a N = 175-turn coil with cross-sectional area, A = 0.0424 m², is decreasing at a steady rate.
When the current drops from 5.43 A to 4.43 A over a period of 0.635 sec, the induced emf is 12.7 V.
(a) What is the inductance of the coil?
L = 0.0461
(b) Calculate the change in the energy density stored in the magnetic field of the coil.
X MJ
Aug
XH
= 4.637e-12
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VIEWStep 5: (b) Calculate the change in the energy density stored in the magnetic field:
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