The current (sense of flow-direction is AB-BC-CD-DA) in the rectangular loop is I2 = 15.0 A. Consider that the the rectangular loop lies in the magnetic field created by a current-carrying conductor which carries a current I = 12.0 A. The dimensions of the rectangular loop are: AB = CD = 0.8 m and AD = BC = 0.30 m. And the separation distance between CD and the current-carrying conductor is 0.50 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. B_ C H 0.50m A D Į

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The current (sense of flow-direction is AB-BC-CD-DA) in the rectangular loop is I2 = 15.0 A. Consider that the
the rectangular loop lies in the magnetic field created by a current-carrying conductor which carries a current I
= 12.0 A. The dimensions of the rectangular loop are: AB = CD = 0.8 m and AD = BC = 0.30 m. And the
separation distance between CD and the current-carrying conductor is 0.50 m. Find the magnitude and direction
of the net force exerted on the loop by the magnetic field created by the wire.
B_ C
H
0.50m
A
D
Į
Transcribed Image Text:The current (sense of flow-direction is AB-BC-CD-DA) in the rectangular loop is I2 = 15.0 A. Consider that the the rectangular loop lies in the magnetic field created by a current-carrying conductor which carries a current I = 12.0 A. The dimensions of the rectangular loop are: AB = CD = 0.8 m and AD = BC = 0.30 m. And the separation distance between CD and the current-carrying conductor is 0.50 m. Find the magnitude and direction of the net force exerted on the loop by the magnetic field created by the wire. B_ C H 0.50m A D Į
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