The current in the following circuit was measured and found to be 2 mA. R1 R2 2k Ohm 3k Ohm .12V R3
The current in the following circuit was measured and found to be 2 mA. R1 R2 2k Ohm 3k Ohm .12V R3
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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This circuit diagram includes:
- A 12V battery.
- Three resistors connected in series, labeled as:
- R1 = 2 kΩ
- R2 = 3 kΩ
- R3 = *Not specifically labeled for value in the text*.
**a. How much power is being delivered by the battery? (Please provide the answer in Engineering Notation.)**
To find the power being delivered by the battery, we first use Ohm's Law to calculate the total resistance in the circuit:
1. **Calculate Total Resistance (R_total):**
Since the resistors are in series, the total resistance is the sum of all individual resistances.
\[
R_{total} = R1 + R2 + R3
\]
Assume \( R3 \) is known from the context or previous problems. For example, if \( R3 \) is approximately 1 kΩ, you get:
\[
R_{total} = 2\,k\Omega + 3\,k\Omega + 1\,k\Omega = 6\,k\Omega
\]
2. **Calculate Power (P):**
Using the formula for power,
\[
P = V \times I
\]
where \( V \) is the voltage of the battery (12V) and \( I \) is the current (2 mA or 0.002 A):
\[
P = 12\,V \times 0.002\,A = 0.024\,W = 24\,mW
\]
Therefore, the power being delivered by the battery is **24 mW**.
(Note: If \( R3 \) has a different value you can substitute the correct value in the equations above to find the appropriate total resistance and power delivered.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff57c5c9b-acb3-4a3d-a39b-55eeff7ee4ad%2F0e1514b4-1e63-45d6-98de-7776b13ea343%2Fznwbny9_processed.png&w=3840&q=75)
Transcribed Image Text:### Circuit Analysis Example
The current in the following circuit was measured and found to be **2 mA**.
This circuit diagram includes:
- A 12V battery.
- Three resistors connected in series, labeled as:
- R1 = 2 kΩ
- R2 = 3 kΩ
- R3 = *Not specifically labeled for value in the text*.
**a. How much power is being delivered by the battery? (Please provide the answer in Engineering Notation.)**
To find the power being delivered by the battery, we first use Ohm's Law to calculate the total resistance in the circuit:
1. **Calculate Total Resistance (R_total):**
Since the resistors are in series, the total resistance is the sum of all individual resistances.
\[
R_{total} = R1 + R2 + R3
\]
Assume \( R3 \) is known from the context or previous problems. For example, if \( R3 \) is approximately 1 kΩ, you get:
\[
R_{total} = 2\,k\Omega + 3\,k\Omega + 1\,k\Omega = 6\,k\Omega
\]
2. **Calculate Power (P):**
Using the formula for power,
\[
P = V \times I
\]
where \( V \) is the voltage of the battery (12V) and \( I \) is the current (2 mA or 0.002 A):
\[
P = 12\,V \times 0.002\,A = 0.024\,W = 24\,mW
\]
Therefore, the power being delivered by the battery is **24 mW**.
(Note: If \( R3 \) has a different value you can substitute the correct value in the equations above to find the appropriate total resistance and power delivered.)
Transcribed Image Text:b. What is the voltage drop across R1?
c. What is the voltage drop across R2?
d. What is the resistance value of R3?
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