The current in an Series RL circuit is described by the following differential equation: R i(t) + L di(t)/(dt) = V0 where R is the resistance, L is the inductance, and V0 is the voltage of the source. a) Show that this is a separable differential equation, and then solve it. (Find i(t) in terms of R, L, V0). b) For a Series RL circuit
The current in an Series RL circuit is described by the following differential equation: R i(t) + L di(t)/(dt) = V0 where R is the resistance, L is the inductance, and V0 is the voltage of the source. a) Show that this is a separable differential equation, and then solve it. (Find i(t) in terms of R, L, V0). b) For a Series RL circuit
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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The current in an Series RL circuit is described by the following differential equation:
R i(t) + L di(t)/(dt) = V0
where R is the resistance, L is the inductance, and V0 is the voltage of the source.
a) Show that this is a separable differential equation, and then solve it. (Find i(t) in terms of R, L, V0).
b) For a Series RL circuit with R = 50 (Ohm) and L = 10 (Henry) and the constant voltage V0 = 100 (Volt) applied at t = 0 by closing of a switch, find the current at t = 0.5 second.
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