The current I in the given network is 1202-90° V Z = (80 - j35) 1202-30° V (b) 0 A (d) 2.38 2143.63° A (a) 2.38 2-23.63° A (c) 2.38 -96.37° A Question 6

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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question 5
The current I in the given network is
1204-90° V
Z = (80 - j35) 2
1204-30° V (G
(b) 0 A
(d) 2.38 143.63° A
(a) 2.38 Z-23.63° A
(c) 2.38 Z-96.37° A
Question 6
For an infinitesimally small dipole in free space, the electric field E, in the far field
is proportional to (e-ikr/r)sine, where k = 21/2. A vertical infinitesimally small
electric dipole (8/ << 1) is placed at a distance h(h > 0) above an infinite ideal
conducting plane, as shown in the figure. The minimum value of h, for which one
of the maxima in the far field radiation pattern occurs at0 = 60°. is
I d!
Infinite conduction plane
(b) 2
(d) 0.52
(a) 0.752
(c) 0.252
Transcribed Image Text:Question 5 The current I in the given network is 1204-90° V Z = (80 - j35) 2 1204-30° V (G (b) 0 A (d) 2.38 143.63° A (a) 2.38 Z-23.63° A (c) 2.38 Z-96.37° A Question 6 For an infinitesimally small dipole in free space, the electric field E, in the far field is proportional to (e-ikr/r)sine, where k = 21/2. A vertical infinitesimally small electric dipole (8/ << 1) is placed at a distance h(h > 0) above an infinite ideal conducting plane, as shown in the figure. The minimum value of h, for which one of the maxima in the far field radiation pattern occurs at0 = 60°. is I d! Infinite conduction plane (b) 2 (d) 0.52 (a) 0.752 (c) 0.252
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