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The current enters to the positive terminal of a device is i(t) = et amps, and the voltage across the device is v(t) = 3 d(i)/dt volt. The amount of energy absorbed (in Joule) in between t= 0 and t = 2 seconds is in the range of (e-16 = 1.125 x 10-7) (a) - 5.89 to 5.90 (c) -4.711 to -4.713 (b)-5.99 to -6.00 (d) -1.49 to -1.51

The current enters to the positive terminal of a device is i(t) = et amps, and the voltage across the device is v(t) = 3 d(i)/dt volt. The amount of energy absorbed (in Joule) in between t= 0 and t = 2 seconds is in the range of (e-16 = 1.125 x 10-7) (a) - 5.89 to 5.90 (c) -4.711 to -4.713 (b)-5.99 to -6.00 (d) -1.49 to -1.51

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The current enters to the positive terminal of a device is i(t) = e-4t amps, and the voltage across the device is v(t) = 3 d(i)/dt volt. The amount of energy absorbed (in Joule) in between t = 0 and t = 2 seconds is in the range of (e-16 1.125 x 10-7) (a) - 5.89 to - 5.90 (c) - 4.711 to -4.713 (b) - 5.99 to -6.00 (d) -1.49 to -1.51
Transcribed Image Text:The current enters to the positive terminal of a device is i(t) = e-4t amps, and the voltage across the device is v(t) = 3 d(i)/dt volt. The amount of energy absorbed (in Joule) in between t = 0 and t = 2 seconds is in the range of (e-16 1.125 x 10-7) (a) - 5.89 to - 5.90 (c) - 4.711 to -4.713 (b) - 5.99 to -6.00 (d) -1.49 to -1.51
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