The cross-sectional area of the bar is 5 cm². Use E = 70 GPa for aluminum, and E = 200 GPa for steel. L. Aluminum Steel Aluminum 80 kN 20 kN 30 kN - 70 kN A B |C 3 m - 4 m 5 m

Elements Of Electromagnetics
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The cross sectional area of the bar is 5cm^2.

Use E = 70GPa for aluminum, and E = 200 GPa for steel

What is the elongation in segment AB (Aluminum)?

a. 7.8571 x10^-3 m

b. 6.8571 x10^-3 m

c. -7.8571 x10^-3 m

d. -6.8571 x10^-3 m

What is the elongation in segment BC (Steel)?

a. -3x10^-3 m

b. 3x10^-3 m

c. 2 x10^-3 m

d. -2 x10^-3 m

What is the elongation in segment CD (Aluminum)?

a. -6.8571 x10^-3 m

b. 6.8571 x10^-3 m

c. -2.8571 x10^-3 m

d. 2.8571 x10^-3 m

What is the total elongation of the bar?

a. 5 x10^-3 m

b. 6 x10^-3 m

c. 4 x10^-3 m

d. -6 x10^-3 m

-Draw and label the diagram correctly, No diagram in the solution will be marked wrong. 
-Shortcut solution will be marked wrong.
- Direction of the assumption of the equilibrium equation must be shown, no direction will be marked wrong.

 
The cross-sectional area of the bar is 5 cm².
Use E = 70 GPa for aluminum, and E = 200 GPa for steel.
L.
Aluminum
Steel
Aluminum
80 kN
20 kN
30 kN
- 70 kN
A
D
B
|C
3 m
- 4 m
5 m-
Transcribed Image Text:The cross-sectional area of the bar is 5 cm². Use E = 70 GPa for aluminum, and E = 200 GPa for steel. L. Aluminum Steel Aluminum 80 kN 20 kN 30 kN - 70 kN A D B |C 3 m - 4 m 5 m-
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