The crane body (with arm) is 333.3 kg and the red block is 80kg. The maximum force that the wheels (A & B) and the arm can take is 4500N and 2000N respectively. The combined crane body moves at 10 km/h and 0° while the arm moves 0.1 m/s and 40°

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Can tutor explain step by step and also the explanation such as like why use that formula and why is it this cannot. 

below is the questions need to answer by using the diagram 

1)Calculate the velocity of the arm, observed by a stationary person on the ground.

2)Draw the FBD of the combined body (crane body, arm and load).

3)Is the combined body stable? Why?

4)Calculate the moment of the following, about wheel A,
i) combined crane body
ii) load mass

5)Which combined body’s component(s) will not fail? Why? (Hint: The crane was initially in equilibrium.)

6)What are the various limits (maximum or minimum) for the combined body to be stable? Explain why.

 

The crane body (with arm) is 333.3 kg and the red block
is 80kg. The maximum force that the wheels (A & B) and
the arm can take is 4500N and 2000N respectively. The
combined crane body moves at 10 km/h and 0° while
the arm moves 0.1 m/s and 40°.
CG of the crane body
X
A
1m
2m
B
1m 1m
3m
Arm
40°
Load
Mass=
80 kg
Transcribed Image Text:The crane body (with arm) is 333.3 kg and the red block is 80kg. The maximum force that the wheels (A & B) and the arm can take is 4500N and 2000N respectively. The combined crane body moves at 10 km/h and 0° while the arm moves 0.1 m/s and 40°. CG of the crane body X A 1m 2m B 1m 1m 3m Arm 40° Load Mass= 80 kg
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Follow-up Question

For question 5, this is my way of calculate wheel A and B to find is the component will fail

is this the correct way ? if not can u explain further and why 

8
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PO
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ACN N
M.M
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New Reuse
Slide Slides
Slide 9 of 12
8
DX
m or minimarke the cardinad
Slides
English (Singapore)
28°C
Mostly cloudy
7.1.6.1.5.1.4.1.3.1.2.1.1.1.0.1.1.1.2.1.3.1.4.1.5.1.6.1.7.1.8.1.9.1
86
4x
-
CA1 Presentation Team 5 ? No Label Saved ✓
Transitions Animations
BIUS ab AV
Font
15
Accessibility: Investigate
16
Slide Show
●
✓19
Aa ✓
ν Α' Α' Α
A
14 13
Record Review
12
11
E
3A=680.6296N
A=226.88N (2d.p)
View Help Acrobat
2-
(m1 * 1) − (A * 3) = m2 * D2
g= 9.8 m/s^2
• m2 = 80= 784N
m1= 333.3=3266.34AN
• D2 = 3 * cos (40) + 1=3.2981m
Search
Q Search
IN
10 9 1876 5 14 1.3 12
Paragraph
i) (m1 * 1) − (A * 3) = m2 * D2
(3266.34*1) – (A * 3) = (784)(3.2981)
3A= (3266.34*1)-(784)(3.2981)
H✓
Since A=226.88N < 4500N, wheel A will not fail
Shapes Arrange Quick
1
O Find
Replace
Select
Editing
2 13 14 1.5 16 ·7 18
0
Styles U
Drawing
5.Which combined body's component(s) will not fail? Why? (Hint: The
crane was initially in equilibrium.) (Wheel A)
Find Wheel A, Take B as pivot,
1m
Create and Share
Adobe PDF
Adobe Acrobat
11
9
O Record
2m
10
CG of the crane body
X
Notes
LIM YOU WEI
Moment = Force *Distance
Sum of clockwise
moments =
Sum of anticlockwise
moments
m1
1m 1m
Dictate
Present in Teams
Voice
12 13
3m
14
Arm
40°
D2
Sensitivity
15 16
9
Sensitivity Designer
Load
Mass=
80 kg
m2
ENG
I
0
H
+44
4)
Designer
0
Share
+ 79%
9:29 am
15/5/2023
X
Transcribed Image Text:8 9 10 11 12 AutoSave On File Home Insert Draw Design X Layout Reset LG Section ✓ Paste Clipboard PO Grand wer intly la will not fall? Whyfint: The -pa - 3448 -ml-11.3-114844 Gravate my body components will not fall? Why? ()ird The www. MACMA Dan menge) will not fall? Why? (tard. The Dedy ball Ented pla N Grace was in bly in aprilie will not fw? Why?)fint: The ACN N M.M se New Reuse Slide Slides Slide 9 of 12 8 DX m or minimarke the cardinad Slides English (Singapore) 28°C Mostly cloudy 7.1.6.1.5.1.4.1.3.1.2.1.1.1.0.1.1.1.2.1.3.1.4.1.5.1.6.1.7.1.8.1.9.1 86 4x - CA1 Presentation Team 5 ? No Label Saved ✓ Transitions Animations BIUS ab AV Font 15 Accessibility: Investigate 16 Slide Show ● ✓19 Aa ✓ ν Α' Α' Α A 14 13 Record Review 12 11 E 3A=680.6296N A=226.88N (2d.p) View Help Acrobat 2- (m1 * 1) − (A * 3) = m2 * D2 g= 9.8 m/s^2 • m2 = 80= 784N m1= 333.3=3266.34AN • D2 = 3 * cos (40) + 1=3.2981m Search Q Search IN 10 9 1876 5 14 1.3 12 Paragraph i) (m1 * 1) − (A * 3) = m2 * D2 (3266.34*1) – (A * 3) = (784)(3.2981) 3A= (3266.34*1)-(784)(3.2981) H✓ Since A=226.88N < 4500N, wheel A will not fail Shapes Arrange Quick 1 O Find Replace Select Editing 2 13 14 1.5 16 ·7 18 0 Styles U Drawing 5.Which combined body's component(s) will not fail? Why? (Hint: The crane was initially in equilibrium.) (Wheel A) Find Wheel A, Take B as pivot, 1m Create and Share Adobe PDF Adobe Acrobat 11 9 O Record 2m 10 CG of the crane body X Notes LIM YOU WEI Moment = Force *Distance Sum of clockwise moments = Sum of anticlockwise moments m1 1m 1m Dictate Present in Teams Voice 12 13 3m 14 Arm 40° D2 Sensitivity 15 16 9 Sensitivity Designer Load Mass= 80 kg m2 ENG I 0 H +44 4) Designer 0 Share + 79% 9:29 am 15/5/2023 X
8
9
10
11
12
AutoSave On
File Home Insert Draw Design
X
Layout
Reset
LG
Section ✓
Paste
Clipboard
= 33*1,A²"(KED=4|
PO
Grand wer intly la will not fall? Whyfint: The
Bare wat inhyls and boot fall? Why? (liet. The
ZE
-pem
3840
380)
crane was infinly is equa
BUSLOM
N
Dedy ball Ented pla
ACN
N
Talking trac the pluce:
M.M
New Reuse
Slide Slides
crae wat inclus will not all? Whyz (flint: The
se
Slide 10 of 12
ponentig) will not fail? Why? (Hint: The
m or minimarke the cardinad
Slides
BX English (Singapore)
28°C
Mostly cloudy
7·1·6·1·5·4·3·2·10 1 2 3 4 5 6 7 8 9
·1·6·
-
CA1 Presentation Team 5 ? No Label Saved ✓
Transitions Animations
BIUS ab AV
Font
15
Accessibility: Investigate
16
●
Slide Show
●
✓19
Aa ✓
14
ν Α' Α' Α
A
13
Record Review
12
11
E
3B-11470.4165N
Search
View Help Acrobat
2-
(m1 * 2)+ (m2*(3cos(40)+4)= B*3
g = 9.8 m/s^2
m2 = 80= 784N
m1= 333.3=3266.34AN
• D2 = 3cos (40) + 1+2+1=6.298m
Paragraph
IN
10 9 1876 5 14 1.3 12
Q Search
i) (m1 * 2)+(m2*(3cos(40)+4)=B*3
(3266.34*2)+(784*(3cos(40)+4) = 3B
H✓
B=3823.47N (2dp)
Since B=3823.47N < 4500N, wheel B will not fail
Shapes Arrange Quick
1
O Find
Replace
Select
Editing
2 13 14 1.5 16 ·7 18
0
5.Which combined body's component(s) will not fail? Why? (Hint: The
crane was initially in equilibrium.) (Wheel B)
Find Wheel B, Take A as pivot,
Styles U
Drawing
1m
Create and Share
Adobe PDF
Adobe Acrobat
11
9
O Record
2m
10
CG of the crane body
X
Notes
LIM YOU WEI
Moment = Force *Distance
Sum of clockwise
moments =
Sum of anticlockwise
moments
m1
1m 1m
Dictate
Present in Teams
Voice
12 13
3m
14
Arm
40°
Sensitivity
15 16
D1
Sensitivity Designer
9
Load
Mass=
80 kg
ENG
m2
I
0
H
+44
4)
Designer
0
Share
+ 79%
9:29 am
15/5/2023
X
Transcribed Image Text:8 9 10 11 12 AutoSave On File Home Insert Draw Design X Layout Reset LG Section ✓ Paste Clipboard = 33*1,A²"(KED=4| PO Grand wer intly la will not fall? Whyfint: The Bare wat inhyls and boot fall? Why? (liet. The ZE -pem 3840 380) crane was infinly is equa BUSLOM N Dedy ball Ented pla ACN N Talking trac the pluce: M.M New Reuse Slide Slides crae wat inclus will not all? Whyz (flint: The se Slide 10 of 12 ponentig) will not fail? Why? (Hint: The m or minimarke the cardinad Slides BX English (Singapore) 28°C Mostly cloudy 7·1·6·1·5·4·3·2·10 1 2 3 4 5 6 7 8 9 ·1·6· - CA1 Presentation Team 5 ? No Label Saved ✓ Transitions Animations BIUS ab AV Font 15 Accessibility: Investigate 16 ● Slide Show ● ✓19 Aa ✓ 14 ν Α' Α' Α A 13 Record Review 12 11 E 3B-11470.4165N Search View Help Acrobat 2- (m1 * 2)+ (m2*(3cos(40)+4)= B*3 g = 9.8 m/s^2 m2 = 80= 784N m1= 333.3=3266.34AN • D2 = 3cos (40) + 1+2+1=6.298m Paragraph IN 10 9 1876 5 14 1.3 12 Q Search i) (m1 * 2)+(m2*(3cos(40)+4)=B*3 (3266.34*2)+(784*(3cos(40)+4) = 3B H✓ B=3823.47N (2dp) Since B=3823.47N < 4500N, wheel B will not fail Shapes Arrange Quick 1 O Find Replace Select Editing 2 13 14 1.5 16 ·7 18 0 5.Which combined body's component(s) will not fail? Why? (Hint: The crane was initially in equilibrium.) (Wheel B) Find Wheel B, Take A as pivot, Styles U Drawing 1m Create and Share Adobe PDF Adobe Acrobat 11 9 O Record 2m 10 CG of the crane body X Notes LIM YOU WEI Moment = Force *Distance Sum of clockwise moments = Sum of anticlockwise moments m1 1m 1m Dictate Present in Teams Voice 12 13 3m 14 Arm 40° Sensitivity 15 16 D1 Sensitivity Designer 9 Load Mass= 80 kg ENG m2 I 0 H +44 4) Designer 0 Share + 79% 9:29 am 15/5/2023 X
Solution
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Follow-up Question

Why Fsin40= 80*9.8

how can I know is Fsin40

 

Solution
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SEE SOLUTION
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