The cost y (in $) to rent a 5-ft by 5-ft storage space for x months is given for two companies, Company A: y=105+45x and Company B: y=48.50x. Determine the number of months for which the cost of renting a storage space would be the same for either company.
The cost y (in $) to rent a 5-ft by 5-ft storage space for x months is given for two companies, Company A: y=105+45x and Company B: y=48.50x. Determine the number of months for which the cost of renting a storage space would be the same for either company.
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
What is the answer for number four?

Transcribed Image Text:The cost y (in $) to rent a 5-ft by 5-ft storage space for x months is given for two companies, Company A:
Y3D105+45x and Company B: y=48.50x. Determine the number of months for which the cost of renting a
storage space would be the same for either company.
Solve the system by using the addition method: 6x+8%3D5 and 3x-2%3D1
9 = 18+X7
(| = he XE)E
3X-2c0.25) = |
05=1
3x
%3D
+ 0.5 *0.5
3.
lay=3
la la
Y3D0.25
%3D
%3D
5=5
5.
%3D
3(05)-216.20) = 1
0.5,0.25)
%3D
Joe invested three times as much money in an account paying 6% simple interest as
she did in an account paying 2% simple interest. If her total interest at the end of 1 yr
is $402.75, find the amount she invested in the 6% account.
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