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The cost te build any section of the shed is the unit cost to build a section multiplied by the number of squere feet of a section. We have the unit costs, so now we need ta find the square faetage of each section in terms of x and/er y. The base Depth Length Area Cest The sides 1 Left sde and right side Since these sides hove the some dimensions, find the area and cost ef the left side and then deuble it. Depth Height Area of beth Cest ef beth 2 Front side and beck side Since these sides have the some dimensions, find the area and cest ef the frent side and then double it. Length Height Area of beth = Cest of beth i The reef Depth Length Area Cost

The cost te build any section of the shed is the unit cost to build a section multiplied by the number of squere feet of a section. We have the unit costs, so now we need ta find the square faetage of each section in terms of x and/er y. The base Depth Length Area Cest The sides 1 Left sde and right side Since these sides hove the some dimensions, find the area and cost ef the left side and then deuble it. Depth Height Area of beth Cest ef beth 2 Front side and beck side Since these sides have the some dimensions, find the area and cest ef the frent side and then double it. Length Height Area of beth = Cest of beth i The reef Depth Length Area Cost

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The cost to buld ony section of the shed is the unit cost ) to build a section multiplied by the rumber of squore feet of a section. We have the unit costs, so now we need to find the square foetage of coch section in terms of x and/or y. 4. The base! Depth Length Area Cest b. The sides: 1 Left side and right side. Since these sides have the some dimensions, find the area and cost of the left side ond then double it. Depth Height Area of beth. Cost of bath 2. Front side and back side. Since these sides have the some dimensions, find the area and cost of the frent side ond then double it. Length = Height = Area of beth Cost of beth The roof: Depth Length Area Cast Now we con write eur cost equation in terms of x and y. d. The objective functien is the total cost to build the shed. Total cost is the cost te build the base and the sides and the root. Since the cost te build the left and right sides are the some (and the front and back) combine these cost terms to get Total Cost (cest of base) (cost of left and right) (cast of front and bock) (cest of roof) After combining like terma Tetal Cast The constraint is that thmeof the shedmust be ef our shed in terms of x and y is (Recall velume of e box is length times width times height) e, The formula for the volume (our volume) (length times width times height) Solve this volume equotion for y Replace y in your cest function to make it o function of x only, When you are done simplifying the cest equation you shauld get two terms one with on , one with on x in the denominator of a frection Present the coefficients of these two terms as reduced froctions. DO NOT APPROXIMATE I would use the MATH FRAC feature on a graphing calculator or the froction option on Desmes to convert this quantity te a froctien Show your work below.
Transcribed Image Text:The cost to buld ony section of the shed is the unit cost ) to build a section multiplied by the rumber of squore feet of a section. We have the unit costs, so now we need to find the square foetage of coch section in terms of x and/or y. 4. The base! Depth Length Area Cest b. The sides: 1 Left side and right side. Since these sides have the some dimensions, find the area and cost of the left side ond then double it. Depth Height Area of beth. Cost of bath 2. Front side and back side. Since these sides have the some dimensions, find the area and cost of the frent side ond then double it. Length = Height = Area of beth Cost of beth The roof: Depth Length Area Cast Now we con write eur cost equation in terms of x and y. d. The objective functien is the total cost to build the shed. Total cost is the cost te build the base and the sides and the root. Since the cost te build the left and right sides are the some (and the front and back) combine these cost terms to get Total Cost (cest of base) (cost of left and right) (cast of front and bock) (cest of roof) After combining like terma Tetal Cast The constraint is that thmeof the shedmust be ef our shed in terms of x and y is (Recall velume of e box is length times width times height) e, The formula for the volume (our volume) (length times width times height) Solve this volume equotion for y Replace y in your cest function to make it o function of x only, When you are done simplifying the cest equation you shauld get two terms one with on , one with on x in the denominator of a frection Present the coefficients of these two terms as reduced froctions. DO NOT APPROXIMATE I would use the MATH FRAC feature on a graphing calculator or the froction option on Desmes to convert this quantity te a froctien Show your work below.
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