The cost, in thousands of dollars, of airing x television commercials during a sports event is given by C(x) = 20 + 4,000x + 0.03x². (a) Find the marginal cost function C'(x). HINT [See Example 1.] C'(x) = Use it to estimate how fast the cost is increasing when x = 4. thousand dollars per television commercial Compare this with the exact cost of airing the fifth commercial. The cost is going up at the rate of $ $ per television commercial. The exact cost of airing the fifth commercial is $ (b) Find the average cost function C, and evaluate C(4). HINT [See Example 2.] C(x)= C(4) = thousand dollars per television commercial What does the answer tell you? The average cost of airing the first four commercials is $ per commercial, . Thus, there is a difference of
The cost, in thousands of dollars, of airing x television commercials during a sports event is given by C(x) = 20 + 4,000x + 0.03x². (a) Find the marginal cost function C'(x). HINT [See Example 1.] C'(x) = Use it to estimate how fast the cost is increasing when x = 4. thousand dollars per television commercial Compare this with the exact cost of airing the fifth commercial. The cost is going up at the rate of $ $ per television commercial. The exact cost of airing the fifth commercial is $ (b) Find the average cost function C, and evaluate C(4). HINT [See Example 2.] C(x)= C(4) = thousand dollars per television commercial What does the answer tell you? The average cost of airing the first four commercials is $ per commercial, . Thus, there is a difference of
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![The cost, in thousands of dollars, of airing \( x \) television commercials during a sports event is given by
\[ C(x) = 20 + 4.000x + 0.03x^2. \]
**(a)** Find the marginal cost function \( C'(x) \). HINT [See Example 1.1]
\[ C'(x) = \]
Use it to estimate how fast the cost is increasing when \( x = 4 \).
\[\_\_\_\_\_\_\_\_\_] thousand dollars per television commercial
Compare this with the exact cost of airing the fifth commercial.
The cost is going up at the rate of $[\_\_\_\_\_\_\_\_\_]$ per television commercial. The exact cost of airing the fifth commercial is $[\_\_\_\_\_\_\_\_\_]$. Thus, there is a difference of $[\_\_\_\_\_\_\_\_\_]$.
**(b)** Find the average cost function \(\overline{C}\), and evaluate \(\overline{C}(4)\). HINT [See Example 2.2]
\[\overline{C}(x) = [\_\_\_\_\_\_\_\_\_]\]
\[\overline{C}(4) = [\_\_\_\_\_\_\_\_\_] \] thousand dollars per television commercial
What does the answer tell you?
The average cost of airing the first four commercials is $[\_\_\_\_\_\_\_\_\_]$ per commercial.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd48171ba-d1cc-47b1-bf9c-8041143384f0%2F38423f66-7756-4265-be4a-d29d75179ad3%2Fd8xp2nj_processed.png&w=3840&q=75)
Transcribed Image Text:The cost, in thousands of dollars, of airing \( x \) television commercials during a sports event is given by
\[ C(x) = 20 + 4.000x + 0.03x^2. \]
**(a)** Find the marginal cost function \( C'(x) \). HINT [See Example 1.1]
\[ C'(x) = \]
Use it to estimate how fast the cost is increasing when \( x = 4 \).
\[\_\_\_\_\_\_\_\_\_] thousand dollars per television commercial
Compare this with the exact cost of airing the fifth commercial.
The cost is going up at the rate of $[\_\_\_\_\_\_\_\_\_]$ per television commercial. The exact cost of airing the fifth commercial is $[\_\_\_\_\_\_\_\_\_]$. Thus, there is a difference of $[\_\_\_\_\_\_\_\_\_]$.
**(b)** Find the average cost function \(\overline{C}\), and evaluate \(\overline{C}(4)\). HINT [See Example 2.2]
\[\overline{C}(x) = [\_\_\_\_\_\_\_\_\_]\]
\[\overline{C}(4) = [\_\_\_\_\_\_\_\_\_] \] thousand dollars per television commercial
What does the answer tell you?
The average cost of airing the first four commercials is $[\_\_\_\_\_\_\_\_\_]$ per commercial.
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