The cost, in thousands of dollars, of airing x television commercials during a sports event is given by C(x) = 150 + 2,600x – 0.06x². (a) Find the marginal cost function C'(x). C'(x) = (b) Use the marginal cost to approximate the cost to air the 5th commercial. Convert your answer to dollars. The cost to air the 5th commercial is approximately × dollars. (c) What is the exact cost to air the 5th commercial? Convert your answer to dollars. The exact cost to air the 5th commercial is × dollars.
The cost, in thousands of dollars, of airing x television commercials during a sports event is given by C(x) = 150 + 2,600x – 0.06x². (a) Find the marginal cost function C'(x). C'(x) = (b) Use the marginal cost to approximate the cost to air the 5th commercial. Convert your answer to dollars. The cost to air the 5th commercial is approximately × dollars. (c) What is the exact cost to air the 5th commercial? Convert your answer to dollars. The exact cost to air the 5th commercial is × dollars.
Chapter1: Making Economics Decisions
Section: Chapter Questions
Problem 1QTC
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![### Cost Function and Marginal Analysis
#### Problem Statement
The cost, in thousands of dollars, of airing \( x \) television commercials during a sports event is given by:
\[ C(x) = 150 + 2.600x - 0.06x^2. \]
#### Questions
**(a) Find the marginal cost function \( C'(x) \).**
\[ C'(x) = \text{(Enter marginal cost function here)} \]
**(b) Use the marginal cost to approximate the cost to air the 5th commercial. Convert your answer to dollars.**
The cost to air the 5th commercial is approximately \(\boxed{\text{(enter approximate cost here)}}\) dollars.
**(c) What is the exact cost to air the 5th commercial? Convert your answer to dollars.**
The exact cost to air the 5th commercial is \(\boxed{\text{(enter exact cost here)}}\) dollars.
#### Explanation:
- **Part (a):** Calculate the marginal cost function, which is the derivative of the cost function. This represents the cost change with respect to the number of commercials aired.
- **Part (b):** Use the marginal cost function to estimate the cost of the additional (5th) commercial. This approximation is common in economic analysis to simplify calculations.
- **Part (c):** Compute the exact cost of airing the 5th commercial by evaluating the difference in cost between airing 5 and 4 commercials.
This exercise involves differentiation and basic cost analysis, core concepts in calculus and economics.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d9af5e6-9fd3-4a9b-a9c8-3b97e891ab83%2F097031c2-71ae-47d2-9149-44b531d0ea29%2Fdnb3ze_processed.png&w=3840&q=75)
Transcribed Image Text:### Cost Function and Marginal Analysis
#### Problem Statement
The cost, in thousands of dollars, of airing \( x \) television commercials during a sports event is given by:
\[ C(x) = 150 + 2.600x - 0.06x^2. \]
#### Questions
**(a) Find the marginal cost function \( C'(x) \).**
\[ C'(x) = \text{(Enter marginal cost function here)} \]
**(b) Use the marginal cost to approximate the cost to air the 5th commercial. Convert your answer to dollars.**
The cost to air the 5th commercial is approximately \(\boxed{\text{(enter approximate cost here)}}\) dollars.
**(c) What is the exact cost to air the 5th commercial? Convert your answer to dollars.**
The exact cost to air the 5th commercial is \(\boxed{\text{(enter exact cost here)}}\) dollars.
#### Explanation:
- **Part (a):** Calculate the marginal cost function, which is the derivative of the cost function. This represents the cost change with respect to the number of commercials aired.
- **Part (b):** Use the marginal cost function to estimate the cost of the additional (5th) commercial. This approximation is common in economic analysis to simplify calculations.
- **Part (c):** Compute the exact cost of airing the 5th commercial by evaluating the difference in cost between airing 5 and 4 commercials.
This exercise involves differentiation and basic cost analysis, core concepts in calculus and economics.
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