The contingency table shows how many people wore (Y) and did not wear (N) seat belts as well as how many survived (S) and died (D) in car accidents in a recent year. Wore seat belt D Survived (S) 370,313 Yes (Y) 175,079 No (N) Total 545,392 Complete parts a through d below. S D a. What is the sample space for a randomly selected individual involved in an auto accident? Use a tree diagram to illustrate the possible outcomes. OA. O C. D D Died (D) 766 1314 2080 Sample space: {SS, SD, DS, DD} B. Y S D b. Using the data in the table, estimate (i) P(D), (ii) P(N). (i) P(D) 0.0038 (Round to four decimal places as needed.) S D Sample space: {YS, YD, NS, ND} Total 371,079 176,393 547,472 *** (ii) P(N)≈ 0.3222 (Round to four decimal places as needed.) c. Estimate the probability that an individual did not wear a seat belt and died. P(N and D) 0.0024 (Round to four decimal places as needed.) d. Based on (b), what would the answer to (c) have been if the events N and D were independent? P(N and D) (Round to four decimal places as needed.) N S D D Sample space: {YS, YS, ND, ND} O D. N N N Sample space: (YY, YN,NY,NN}
The contingency table shows how many people wore (Y) and did not wear (N) seat belts as well as how many survived (S) and died (D) in car accidents in a recent year. Wore seat belt D Survived (S) 370,313 Yes (Y) 175,079 No (N) Total 545,392 Complete parts a through d below. S D a. What is the sample space for a randomly selected individual involved in an auto accident? Use a tree diagram to illustrate the possible outcomes. OA. O C. D D Died (D) 766 1314 2080 Sample space: {SS, SD, DS, DD} B. Y S D b. Using the data in the table, estimate (i) P(D), (ii) P(N). (i) P(D) 0.0038 (Round to four decimal places as needed.) S D Sample space: {YS, YD, NS, ND} Total 371,079 176,393 547,472 *** (ii) P(N)≈ 0.3222 (Round to four decimal places as needed.) c. Estimate the probability that an individual did not wear a seat belt and died. P(N and D) 0.0024 (Round to four decimal places as needed.) d. Based on (b), what would the answer to (c) have been if the events N and D were independent? P(N and D) (Round to four decimal places as needed.) N S D D Sample space: {YS, YS, ND, ND} O D. N N N Sample space: (YY, YN,NY,NN}
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
5.
Transcribed Image Text:The contingency table shows how many people wore (Y) and did not wear (N) seat belts as well as how many survived (S) and died (D) in car accidents in a recent year.
Wore seat belt
Died (D)
O
Survived (S)
370,313
Yes (Y)
766
175,079
1314
No (N)
Total
545,392
2080
Complete parts a through d below.
S
D
a. What is the sample space for a randomly selected individual involved in an auto accident? Use a tree diagram to illustrate the possible outcomes.
OA
O C.
D
S
D
Sample space:
{SS, SD, DS, DD}
B.
Y
S
D
b. Using the data in the table, estimate (i) P(D), (ii) P(N).
(i) P(D) 0.0038 (Round to four decimal places as needed.)
S
D
Sample space:
{YS, YD, NS, ND}
Total
371,079
176,393
547,472
C
***
(ii) P(N) 0.3222 (Round to four decimal places as needed.)
c. Estimate the probability that an individual did not wear a seat belt and died.
P(N and D) 0.0024 (Round to four decimal places as needed.)
d. Based on (b), what would the answer to (c) have been if the events N and D were independent?
P(N and D)
(Round to four decimal places as needed.)
Y
N
S
D
Sample space:
{YS, YS, ND, ND}
O D.
Y
N
N
Y
N
Sample space:
{YY,YN, NY,NN}
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