The conductivity of a 0.05M solution of acetic acid at 18⁰C is 4.4×10-4 (ohms)-1cm-1. Limiting molar conductivity of acetic acid at the same temperature is 387 (Ohms)-1cm². Calculate the dissociation constant (Ka) of acetic acid? b) The resistivity of aluminum is 2.824×10-8 ohms.m. Calculate the potential drop across a piece of aluminum wire that is 2.0 mm in diameter and 1.00 m long. Assume current is 1.25 A.
The conductivity of a 0.05M solution of acetic acid at 18⁰C is 4.4×10-4 (ohms)-1cm-1. Limiting molar conductivity of acetic acid at the same temperature is 387 (Ohms)-1cm². Calculate the dissociation constant (Ka) of acetic acid? b) The resistivity of aluminum is 2.824×10-8 ohms.m. Calculate the potential drop across a piece of aluminum wire that is 2.0 mm in diameter and 1.00 m long. Assume current is 1.25 A.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please assist with the following sub questions of question 1.
a) The conductivity of a 0.05M solution of acetic acid at 18⁰C is 4.4×10-4 (ohms)-1cm-1. Limiting molar conductivity of acetic acid at the same temperature is 387 (Ohms)-1cm². Calculate the dissociation constant (Ka) of acetic acid?
b) The resistivity of aluminum is 2.824×10-8 ohms.m. Calculate the potential drop across a piece of aluminum wire that is 2.0 mm in diameter and 1.00 m long. Assume current is 1.25 A.
C) Calculate the conductance and conductivity of a metal if the resistivity of the metal is 2.824×10-8 ohms.m, with resistance of 9.0×10-3 ohms when current is 1.25 A.
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